Answer:
the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111
Explanation:
Given the data in the question;
To determine the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose, first we get the molar masses of both alanine and glucose
we know that;
Molar mass of alanine ( C₃H₇NO₂ ) = 89.09 g/mol
Molar mass of glucose ( C₆H₁₂O₆ ) = 180.16 g/mol
now, { metabolizing each gram }
moles of alanine = mass taken / molar mass
= 1g / 89.09 g/mol = 1/89.09 moles
moles of glucose = mass taken / molar mass
= 1g / 180.16 g/mol = 1/180.16 moles
In each molecule of alanine, we have 3 atoms of carbon.
Also, in each molecules of glucose, we have 6 atoms of carbon
so,
number of moles of Carbons in alanine = 3 × 1/89.09 moles = 0.03367
number of moles of Carbons in glucose = 6 × 1/180.16 moles = 0.0333
so ratio of energy will be the ratio of carbon atoms, which is;
⇒ 0.03367 / 0.0333 = 1.0111
Therefore, the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111
