In order to get a weight reduction, a 15 cm diameter solid steel shaft rotating at 150 rpm. The shaft is 3 meters long and the d
ensity of steel is 8.05 g/cm3. This shaft is replaced by a Titanium (p = 4.506 g/cm3) tube with a 15 cm OD and an 10 cm ID. Determine the reduction in kinetic energy in this system.
1 answer:
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Answer:
Explanation:
Given conditions
1)The stress on the blade is 100 MPa
2)The yield strength of the blade is 175 MPa
3)The Young’s modulus for the blade is 50 GPa
4)The strain contributed by the primary creep regime (not including the initial elastic strain) was 0.25 % or 0.0025 strain, and this strain was realized in the first 4 hours.
5)The temperature of the blade is 800°C.
6)The formula for the creep rate in the steady-state regime is dε /dt = 1 x 10-5 σ4 exp (-2 eV/kT)
where: dε /dt is in cm/cm-hr σ is in MPa T is in Kelvink = 8.62 x 10-5 eV/K
Young Modulus, E = Stress, /Strain, ∈
initial Strain,
creep rate in the steady state
but Tinitial = 0
solving the above equation,
we get
Tfinal = 2459.82 hr