In order to get a weight reduction, a 15 cm diameter solid steel shaft rotating at 150 rpm. The shaft is 3 meters long and the d
ensity of steel is 8.05 g/cm3. This shaft is replaced by a Titanium (p = 4.506 g/cm3) tube with a 15 cm OD and an 10 cm ID. Determine the reduction in kinetic energy in this system.
1 answer:
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Answer: the average velocity decreases
Explanation:
From the provided data we have:
Vessel avg. diameter[mm] number
Aorta 25.0 1
Arteries 4.0 159
Arteioles 0.06 1.4*10^7
Capillaries 0.012 2.9*10^9
from the information, let be the mass flow rate,
is density, n number of vessels, and A is the cross-section area for each vessel
the flow rate is constant so it is equal for all vessels,
The average velocity is related to the flow rate by:
we clear the side where v is in:
area is π*R^2 where R is the average radius of the vessel (diameter/2)
we get:
you can directly see in the last equation that if we go from the aorta to the capillaries, the number of vessels is going to increase ( n will increase and R is going to decrease ) . From the table, R is significantly smaller in magnitude orders than n, therefore, it wont impact the results as much as n. On the other hand, n will change from 1 to 2.9 giga vessels which will dramatically reduce the average blood velocity
Answer:
V = 125.7m/min
Explanation:
Given:
L = 400 mm ≈ 0.4m
D = 150 mm ≈ 0.15m
T = 5 minutes
F = 0.30mm ≈ 0.0003m
To calculate the cutting speed, let's use the formula :
We are to find the speed, V. Let's make it the subject.
Substituting values we have:
V = 125.68 m/min ≈ 125.7 m/min
Therefore, V = 125.7m/min
Answer:
The answer is below
Explanation:
Given that:
Diameter (D) = 0.03 mm = 0.00003 m, length (L) = 2.4 mm = 0.0024 m, longitudinal tensile strength , Fracture strength
a) The critical length () is given by:
The critical length (4.5 mm) is greater than the given length, hence th composite can be produced.
b) The volume fraction (Vf) is gotten from the formula: