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barxatty [35]
1 year ago
15

The y component of a vector R of magnitude k = Bcm shown in the figure below is Ky = +6 cm. What is the direction of this vector

(The angle 8 that makes K with the x axis)?

Physics
1 answer:
WARRIOR [948]1 year ago
6 0

Given

The y-component of vector K is

K_y=6\text{ cm}

The magnitude of vector K is , K=8 cm

To find

The angle

\theta

Explanation

Resolving K along its y-component we have,

\begin{gathered} K_y=Ksin\theta \\ \Rightarrow6=8sin\theta \\ \Rightarrow sin\theta=\frac{3}{4} \\ \Rightarrow\theta=48.59\text{ }^o \end{gathered}

Conclusion

The angle made with the x-axis is

48.59^o

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A packing crate rests on a horizontal surface. It is acted on by three horizontal forces: 600 N to the left, 200 N to the right,
egoroff_w [7]

Answer:

The resultant force would (still) be zero.

Explanation:

Before the 600-N force is removed, the crate is not moving (relative to the surface.) Its velocity would be zero. Since its velocity isn't changing, its acceleration would also be zero.

In effect, the 600-N force to the left and 200-N force to the right combines and acts like a 400-N force to the left.

By Newton's Second Law, the resultant force on the crate would be zero. As a result, friction (the only other horizontal force on the crate) should balance that 400-N force. In this case, the friction should act in the opposite direction with a size of 400 N.

When the 600-N force is removed, there would only be two horizontal forces on the crate: the 200-N force to the right, and friction. The maximum friction possible must be at least 200 N such that the resultant force would still be zero. In this case, the static friction coefficient isn't known. As a result, it won't be possible to find the exact value of the maximum friction on the crate.

However, recall that before the 600-N force is removed, the friction on the crate is 400 N. The normal force on the crate (which is in the vertical direction) did not change. As a result, one can hence be assured that the maximum friction would be at least 400 N. That's sufficient for balancing the 200-N force to the right. Hence, the resultant force on the crate would still be zero, and the crate won't move.

6 0
3 years ago
A 75.0-kg ice skater moving at 10.0 m/s crashes into a stationary skater of equal mass. After the collision, the two skaters mov
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Answer:

Explanation:

Momentum change for either skater is mΔv = 75.0(5.0) = 375 kg•m/s

As a change in momentum is equal to an impulse

375 = FΔt

F = 375/0.100 = 3750 N

As 3750 N < 4500 N no bones are broken.

4 0
3 years ago
Which statement best explains why atoms form chemical bonds with other atoms?
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Because atoms is something that pops or has bubbles in it
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3 years ago
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Class 1 lever

Explanation:

In a class 1 lever, the fulcrum is placed between the effort and the load. This lever systems is the most common.

  • The effort is the force input and the load is the force output
  • The fulcrum is a hinge between the load and effort.
  • Movement of the effort and load are in opposite directions.
  • There are other classes of lever like the class 2 and 3.
  • They all have different load, fulcrum and effort configurations

learn more:

Load related problems brainly.com/question/9202964

Torque brainly.com/question/5352966

#learnwithBrainly

3 0
3 years ago
At a location near the equator, the earth’s magnetic field is horizontal and points north. An electron is moving vertically upwa
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Answer:

2. west

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Given an electron is moving vertically upward from ground.

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According to Fleming right hand rule the direction of the magnetic that acts on the electron is west.

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