Question

The y component of a vector R of magnitude k = Bcm shown in the figure below is Ky = +6 cm. What is the direction of this vector (The angle 8 that makes K with the x axis)?

Answer 1

Given

The y-component of vector K is

$K_y=6\text{ cm}$

The magnitude of vector K is , K=8 cm

To find

The angle

$\theta$

Explanation

Resolving K along its y-component we have,

$\begin{gathered} K_y=Ksin\theta \\ \Rightarrow6=8sin\theta \\ \Rightarrow sin\theta=\frac{3}{4} \\ \Rightarrow\theta=48.59\text{ }^o \end{gathered}$

Conclusion

The angle made with the x-axis is

$48.59^o$