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3 years ago

Every atom of the ____ carbon has 6 protons.

Physics

1 answer:

miss Akunina [59]3 years ago

7 0

Hi, the answer for this question is element!

Hope this helped!

Plz mark brainliest!

~Nate

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A student walks a distance of 3 km in 20 minutes calculate his average speed

serg [7]

Answer:

His average speed is 0.15 kilometer per minute or 2.5 meters per second.

Explanation:

average speed = distance/time

x = 3 km/20 minutes

x = 0.15

—

x = 3000 m/1200 s

x = 2.5

4 0

3 years ago

What are 3 wether instuerments i know anemometer and barometer but the third one and what there job!!

BaLLatris [955]

Well, those are good ones. Now how about a thermometer to measure the temperature ?

7 0

3 years ago

A tray filled with ice is removed from the freezer. After a short period of time, the ice begins to melt.

Sav [38]

A: decreases in specific heat capacity

3 0

3 years ago

We push a 38.4-kg box across the floor at constant velocity. If we are pushing a horizontal force of 238 N, find the coefficient

zmey [24]

Answer: 0.62

Explanation:

Coefficient of friction is defined as the ratio of the moving force (Fm) acting on a body to the normal reaction (R).

Note that the normal reaction acts vertically on the object and is equal to the objects weight (W) i.e W=R

Since W = mg, W = 38.4 ×10

W= 384N =R

Normal reaction = 384N

The horizontal force acting on the body will be the moving force which is 238N

Coefficient of friction = Fm/R

Coefficient of friction = 238/384

Coefficient of friction = 0.62

Therefore, coefficient of kinetic friction between the box and the floor is 0.62

5 0

4 years ago

by how many times occur in the force of attraction between two bodies change when the distance between then is reduced to one th

xenn [34]

Answer:

The force is now 9 times the original force

Explanation:

Coulomb's Law

The electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Coulomb's formula is:

$\displaystyle F=k\frac{q_1q_2}{d^2}$

Where:

$k=9\cdot 10^9\ N.m^2/c^2$

q1, q2 = the particles' charge

d= The distance between the particles

Suppose the distance is reduced to d'=d/3, the new force F' is:

$\displaystyle F'=k\frac{q_1q_2}{\left(\frac{d}{3}\right)^2}$

$\displaystyle F'=k\frac{q_1q_2}{\frac{d^2}{9}}$

$\displaystyle F'=9k\frac{q_1q_2}{d^2}$

$\displaystyle F'=9F$

The force is now 9 times the original force

8 0

3 years ago