Answer:
Force = 35 N
Explanation:
From Newton's third law of motion, the boy must apply a force greater than the weight of the sled to lift it.
weight of sled = mg
where m is its mass and g the force of gravity on it.
weight of sled = 50 N
Force applied by the boy on the sled = 15 N
Since the force applied on the sled by the boy is lesser than the weight of the sled, then;
Force that the sled exerts on the student = 50 - 15
= 35 N
The force exerted by the sled on the student is 35 N.
Answer:
The force required to move the quarterback with linebacker is <u>1215 N</u>
Explanation:
Using Newton's second law, it is established that F = Ma
Where F is net force acting on the system, a is the acceleration and M is mass of the two object 
Now consider both 
as a system, so net force acting on the system is 
Substitute the given values in the above formula,
Force = 1215 N
<u>1215 N </u>is the force required to move the quarterback with linebacker.
Answer:
A. 1.172 metres
B. 6.82 Ns
C. 4.796 m/s
Explanation:
The total initial momentum is gotten by multiplying the mass and initial velocity of the both bodies.
The 1.40 kg block is at rest so velocity is zero and has no momentum.
The bullet of mass 22 g = 0.022 kg with velocity of 310 m/s
Momentum = 310*0.022
Momentum = 6.82 Ns.
If the bullet gets embedded they will both have common velocity v
6.82 = (0.022+1.40)v
6.82 = 1.422v
V = 6.82/1.422
V = 4.796 m/s
How high the block will rise after the bullet is embedded is given by
H = (U²Sin²tita)/2g
Where tita is 90°
H = (4.796² * sin²(90))/(2*9.81)
H =( 23.001616*1)/19.62
H = 1.172 metres
