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madreJ [45]
3 years ago
5

Two astronauts are 1.40 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via electr

omagnetic waves. The time it takes for sound waves to travel at 328 m/s through the air between the astronauts equals the time it takes for the electromagnetic waves to travel to the earth. How far away from the earth is the spaceship?
Physics
1 answer:
ivann1987 [24]3 years ago
8 0

Answer:

The spaceship is placed at a distance of 1.28\times 10^6\ meters from the Earth.

Explanation:

Distance between two astronauts, d = 1.4 m  

The time it takes for sound waves to travel at 328 m/s through the air between the astronauts equals the time it takes for the electromagnetic waves to travel to the earth.

For sound, time taken is given by :

t=\dfrac{1.4}{328}\ ........(1)

For electromagnetic wave, time taken to travel the Earth is :

t=\dfrac{d}{3\times 10^8}\ ........(2)

d is the distance from the Earth to the spaceship.

As time are same :

\dfrac{d}{3\times 10^8}=\dfrac{1.4}{328}

d=\dfrac{1.4}{328}\times 3\times 10^8\\\\d=1.28\times 10^6\ m

So, the spaceship is placed at a distance of 1.28\times 10^6 meters from the Earth.

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The correct formula to use for the situation given above is: F = MA, where F is the applied force, M is the mass of the object and A is the acceleration.

From the details given in the question, we are told that:

F = 18, 400N

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A = 18,400 / 0.145 = 126,896.55 = 1.27 *10^5.

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a) -1.25 rev/s² and 23.3 rev

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Explanation:

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time 't'= 4 s

angular acceleration 'αФ_Z'=?

constant angular acceleration equation is given by,

ωФ_Z= ωФ_o_z + αФ_Zt

αФ_Z= (ωФ_Z - ωФ_o_z )/t => (3.333-8.333)/4

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ωФ_o_z = 3.333 rev/s

αФ_Z= -1.25 rev/s²

ωФ_Z= ωФ_o_z + αФ_Zt

t= (ωФ_Z - ωФ_o_z)/αФ_Z => (0- 3.333)/-1.25

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You can make a smoothie in a blender with a power of 400 watts and an efficiency of 85 percent. How much energy is actually bein
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