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Anton [14]
3 years ago
8

What is the molality of a solution formed by dissolving 1.12 mol of kcl in 16.0 mol of water?

Chemistry
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

The molality of the solution is 3.45 mol/kg

Explanation:

Molality is a type of concentration which shows the moles of solute contained in  1 kg of solvent.

Moles of salt (KCl) = 1.12 moles

Moles of solvent (H₂O) = 18 moles

Let's convert the moles of solvent to mass (mol . molar mass)

18 m . 18g/m = 324 grams

We convert grams to kg → 324 g / 1000 = 0.324 kg

Now we can reach molality

1.12mol / 0.324 kg = 3.45 m

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The bonds of four salts (MgBr2, NaCl, MgCl2, and NaBr) are evaluated for ionic character based on electronegativity differences
sammy [17]

Answer:

MgBr2 < MgCl2 < NaBr < NaCl

Explanation:

In order to determinate ionic character, we have to subtract the electronegativity from the elements involved. This is known as Pauling rule.

MgBr2 > ΔΕΝ = 1.8

NaCl > ΔΕΝ = 2.3

MgCl2 > ΔΕΝ = 2

NaBr > ΔΕΝ = 2.1

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Explanation:

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3 years ago
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lorasvet [3.4K]
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7 0
2 years ago
What is the limiting reactant if 12 moles of p4 react with 15 moles of o2?.
brilliants [131]

Answer:

see explanation

Explanation:

To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.

    P₄      +     5O₂       => 2P₂O₅

12/1 = 12      15/5 = 3

O₂ is the limiting reactant. P₄ will be in excess when rxn stops.

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3 years ago
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