C2H5OH (l) + 3 O2 (g) = 2 CO2 (g)+ 3 H2O (l/g)
Answer
Magma is less dense compared to the surrounding rock.
the overlying rock creates pressure which forces the magma to be directed upward.
Explanation:
at high temperatures the magma is liquid form with the high energy which causes the formation of bonds and the pressure build up creates the increase channeling of the liquid.as the temperature decreases the magma moves into the surface
She threw the marshmallow at a speed of around 4.76 m/s.The formula for the horizontal range gives the velocity.
<h3>What is projectile motion?</h3>
The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.
The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.
Given data;
The marshmallow was thrown at a distance of 2 meters
Range,R = 3 m
Initial velocity,u
The angle at which the marshmallow was thrown,θ = 30°
The acceleration due to gravity,g = 9.81 m/s²
The projectile's motion is divided into two parts: horizontal and vertical motion.
![\rm R = \frac{u^2sin2 \theta }{g} \\\\ \rm R = \frac{u^2sin2 \times (30) }{9.81} \\\\ u^2=\frac{2 \times 9.81 }{sin 60^0} \\\\ u^2=22.66 \\\\ u=4.76 \ m/sec](https://tex.z-dn.net/?f=%5Crm%20R%20%3D%20%5Cfrac%7Bu%5E2sin2%20%5Ctheta%20%7D%7Bg%7D%20%5C%5C%5C%5C%20%5Crm%20R%20%20%3D%20%5Cfrac%7Bu%5E2sin2%20%5Ctimes%20%2830%29%20%7D%7B9.81%7D%20%5C%5C%5C%5C%20u%5E2%3D%5Cfrac%7B2%20%5Ctimes%209.81%20%7D%7Bsin%2060%5E0%7D%20%5C%5C%5C%5C%20u%5E2%3D22.66%20%5C%5C%5C%5C%20u%3D4.76%20%5C%20m%2Fsec)
Hence, she throws the marshmallow at a speed of 4.76 m/sec.
To learn more about the projectile motion refer to the link;
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A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume increases to 30.0 ml, at constant temperature is 0.25atm.
On constant temperature, the pressure and volume relation become constant before and after the change in quantitities have occurred.
According to Boyle's Law,
P₁V₁ = P₂V₂
where, P₁ is pressure exerted by the gas initially
V₁ is the volume of gas initially
P₂ is pressure exerted by the gas finally
V₂ is the volume of gas finally
Given,
P₁ = 1.5 atm
V₁ = 5 ml
V₂ = 30 ml
P₂ =?
On substituting the given values in the above equation:
P₁V₁ = P₂V₂
1.5 atm × 5 ml = P₂ × 30 ml
P₂ = 0.25 atm
Hence, pressure exerted by the gas is 0.25atm.
Learn more about Boyle's Law here, brainly.com/question/1437490
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As the distance from a charged particle, "q", increases, the electric potential decreases.
<h3>
Electric potential between particles</h3>
The electric potential between particles is the work done in moving a unit charge from infinity to a certain point against the electrical resistance of the field.
V = Kq/r
where;
- K is Coulomb's constant
- q is the magnitude of the charge
- r is the distance between the charges
Thus, from the formula above, as the distance from a charged particle, "q", increases, the electric potential decreases.
Learn more about electric potential here: brainly.com/question/14306881
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