Answer:
![490.5\ \text{N/m}](https://tex.z-dn.net/?f=490.5%5C%20%5Ctext%7BN%2Fm%7D)
Explanation:
m = Mass attached to spring = 14 kg
g = Acceleration due to gravity = ![9.81\ \text{m/s}^2](https://tex.z-dn.net/?f=9.81%5C%20%5Ctext%7Bm%2Fs%7D%5E2)
x = Displacement of spring = ![78-50=28\ \text{cm}](https://tex.z-dn.net/?f=78-50%3D28%5C%20%5Ctext%7Bcm%7D)
k = Spring constant
The force balance of the system is given by
![kx=mg\\\Rightarrow k=\dfrac{mg}{x}\\\Rightarrow k=\dfrac{14\times 9.81}{0.28}\\\Rightarrow k=490.5\ \text{N/m}](https://tex.z-dn.net/?f=kx%3Dmg%5C%5C%5CRightarrow%20k%3D%5Cdfrac%7Bmg%7D%7Bx%7D%5C%5C%5CRightarrow%20k%3D%5Cdfrac%7B14%5Ctimes%209.81%7D%7B0.28%7D%5C%5C%5CRightarrow%20k%3D490.5%5C%20%5Ctext%7BN%2Fm%7D)
The spring constant for that spring is
.
21) Acceleration from D to E: ![1 m/s^2](https://tex.z-dn.net/?f=1%20m%2Fs%5E2)
22) The acceleration of the bus from D to E is ![1 m/s^2](https://tex.z-dn.net/?f=1%20m%2Fs%5E2)
Explanation:
21)
The acceleration of an object is equal to the rate of change of velocity of the object. Mathematically:
![a=\frac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7D%7Bt%7D)
where
u is the initial velocity
v is the final velocity
t is the time elapsed
In this problem, we want to measure the acceleration of the bus from point D to point E. We have:
- Initial velocity at point D: u = 0
- Final velocity at point E: v = 5 m/s
- Time elapsed from D to E: t = 21 - 16 = 5 s
Therefore, the acceleration between D and E is
![a=\frac{5-0}{5}=1 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B5-0%7D%7B5%7D%3D1%20m%2Fs%5E2)
22) This question is the same as 21), so the result is the same.
Learn more about acceleration:
brainly.com/question/9527152
brainly.com/question/11181826
brainly.com/question/2506873
brainly.com/question/2562700
#LearnwithBrainly
plastics, Styrofoam hOPE THIS HELPS
Two neutral objects will not have any electric force of attraction or repulsion between them.
<h3>What is the condition for the electric force between two objects?</h3>
As we know from the electrostatics that whenever there are two charges having a positive charge on one and a negative on the other will attract each other
similarly, if they are having like charges which are both of them having positive or both of them having a negative charge then there will be a force of repulsion between them.
But if both of them or even one of them is neutral then there will not be any electric force between them.
Thus neutral objects will not have any electric force of attraction or repulsion between them.
To know more about the nature of charged particles follow
brainly.com/question/22492496
Answer:
![v=2019.09\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D2019.09%5C%20m.s%5E%7B-1%7D)
Explanation:
Given:
- time taken by the sun to complete one revolution,
![t=601.2\ hr](https://tex.z-dn.net/?f=t%3D601.2%5C%20hr)
- radial distance of the sunspot,
![r=6.955\times 10^8\ m.s^{-1}](https://tex.z-dn.net/?f=r%3D6.955%5Ctimes%2010%5E8%5C%20m.s%5E%7B-1%7D)
<u>Therefore, angular speed of rotation of sun:</u>
![\omega=\frac{2\pi}{601.2\times 3600} \ rad.s^{-1}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B2%5Cpi%7D%7B601.2%5Ctimes%203600%7D%20%5C%20rad.s%5E%7B-1%7D)
<u>Now the tangential velocity of the sunspot can be given by:</u>
![v=r.\omega](https://tex.z-dn.net/?f=v%3Dr.%5Comega)
![v=6.955\times 10^8\times \frac{2\pi}{601.2\times 3600}](https://tex.z-dn.net/?f=v%3D6.955%5Ctimes%2010%5E8%5Ctimes%20%5Cfrac%7B2%5Cpi%7D%7B601.2%5Ctimes%203600%7D)
![v=2019.09\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D2019.09%5C%20m.s%5E%7B-1%7D)