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serg [7]
3 years ago
13

A punch must cut a hole 30mm diameter in a sheet of steel 2mm thick. The ultimate shear

Engineering
1 answer:
Anettt [7]3 years ago
7 0

2+2=3

4+5=7

tex]\purple{\rule{45pt}{7pt}}\blue{\rule{45pt}{999999pt}}tex]

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(a) Define a slip system. (b) Cite one slip system for the simple cubic crystal structure. (c) One slip system for the BCC cryst
Lemur [1.5K]

Answer:

I'm gonna say D.

4 0
3 years ago
Type the correct answer in the box. Spell all words correctly.
SSSSS [86.1K]

Answer: Type the correct answer in the box. Spell all words correctly.

Which design principle indicates disparity between adjacent parts of a design to give it a striking overall look?

-blank- is disparity between adjacent parts of a design to give it a striking overall look.

Explanation:

8 0
2 years ago
The magic square is an arrangement of numbers in a square grid in such a way that the sum of the numbers in each row, and in eac
Yuki888 [10]

Answer:

See the explanation for the answer;

Explanation:

Matlab code is as given below

-------------------------------------------------------------------------------------Start of code

% Program to create a magic square and verify it

clc

M= magic(5)

% To find sum of elements of each row

r1= sum(M(1,:))      % Sum of row 1

r2= sum(M(2,:))      % Sum of row 2

r3= sum(M(3,:))      % Sum of row 3

r4= sum(M(4,:))      % Sum of row 4

r5= sum(M(5,:))      % Sum of row 5

% To find sum of each coloumn

c1= sum(M(:,1))      % Sum of coloumn 1

c2= sum(M(:,2))      % Sum of coloumn 2

c2= sum(M(:,3))      % Sum of coloumn 3

c2= sum(M(:,4))      % Sum of coloumn 4

c2= sum(M(:,5))      % Sum of coloumn 5

% To find sum of diagonal

d1= sum(diag(M))               % Sum of principal diagonal elements

d2= sum(diag(fliplr(M)))      

-------------------------------------------------------------------------------End of code

Following results are obtained when executed.

M =

   17    24     1     8    15

   23     5     7    14    16

    4     6    13    20    22

   10    12    19    21     3

   11    18    25     2     9

r1 =

   65

r2 =

   65

r3 =

   65

r4 =

   65

r5 =

   65

c1 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

d1 =

   65

d2 =

   65

3 0
3 years ago
Name two types of fabric testers and explain how they work.
Lilit [14]

Answer:

Merchandisers are the key persons in apparel business. They work as a bridge between buyer and seller. Merchandisers have to do various tasks from order execution to final dispatch. Developing Lab dip is one of the primary jobs for a merchandiser to start an order execution. They need to run for lab dip approval. Though this would be an easy task, sometimes big mistakes may occur. They have to do different fabric tests as buyer required. In this article I will briefly described different types of fabric test are completed by garment merchandisers.

It is necessary to validate the information that the mill or manufacturer gives you. This is normally done by having fabric tested by an accredited testing house (internationally recognized) either in the country of manufacturer or locally in your head office. Some companies have their own equipment and employ qualified fabric technicians to carry out the testing at their headquarters. When using an accredited testing house, it will not matter in which country the test is done, because the test has to be carried out to the agreed method, and no matter which country does the test, it will be done in exactly the same way. As the fabric construction is such an important part of the garment, when finalized, the fiber composition, weight, and yarn count should be added to your contract with the supplier.

The testing house will give you guidance on the result you should be achieving and the method that you should be using.

4 0
4 years ago
Ohm's law states that the current (I) in amps equals the voltage (E) in volts decided by the resistance (R) in ohm's. If you con
Hitman42 [59]

Answer:

1.14 * 10^-3  amperes

Explanation:

According to ohms law

V = IR   ---- ( 1 )

V = voltage  = 2.4 * 10^3 v

I = current  = ?

R = resistance =  2.1 * 10^6 Ω

from equation 1

I = V / R

 = ( 2.4 * 10^3 ) / (2.1 * 10^6 )

 = 1.14 * 10^-3  amperes

7 0
3 years ago
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