Answer:
The answer to your question is m = 1.6
Explanation:
Data
mass of NaCl = 111 g
volume of water = 1.2 L
Molality = ?
Formula
Molality = number of moles / volume (L)
Process
1.- Calculate the moles of NaCl
Molecular mass = 23 + 35.5 = 58.5 g
1 mol of ------------------- 58.5 g
x -------------------- 111 g
x = (111 x 1) / 58.5
x = 1.897 moles of NaCl
2.- Calculate the mass of water
density of water = 997 kg/m³
mass = volume x density
mass = 0.0012 x 997
mass = 1.19 kg
3.- Calculate molality
m = 1.897/1.19
m = 1.6
Homogeneous mixture made up of two or more substances
Answer:
Solution
Explanation:
An homogenous mixture made up of two or more substances is called a Solution.
Solutions are homogenous mixtures of solutes and solvents.
- In a solution, the solute particles are distributed uniformly in the solvent.
- The solute is the substance that is dissolved to make the solution.
- It is usually present in smaller amount than the solvent
- The solvent is the dispersing medium which allows for the solute to go into solution.
1s^2 2s^2 2p^6 3s^2 3p^3
noble gas configuration: [Ne] 3s^2 3p^3
Standard temperature and pressure are 0°C and 1 atmosphere, and of course their equivalents in other units. 0°C=273K, 1 Atm = 101.3 KPa.
From the choices given, the correct answer is (3).
Answer:
THE SPECIFIC HEAT OF ALUMINIUM IS 0.900 Jg^-1K^-1
Explanation:
To solve this question, follow the following steps listed below:
1. Write the formulae for heat change in a reaction
Heat = m c ΔT
2. Write out their values and convert to standard units.
m = mass of aluminum = 18.3g
Heat = 481 J
T2 = final temperature = 46.6°C = 273 + 46.6 = 319.6 K
T1 = initial temperature = 17.4 °C = 17.4 + 273 K = 290.4K
C = specific heat capacity of aluminum = ?
3. Solve for the specific heat of aluminium
c = Heat / m ΔT
c = 481 J / 18.3 g * ( 319.6 - 290.4) K
c = 481 / 18.3 * 29.2
c = 481 / 534.36
c = 0.900 Jg^-1K^-1
In conclusion, the specific heat capacity of aluminum is 0.900 Jg^-1K^-1.
