A runner first runs a displacement A of 3.20 km due south, and then a second displacement B that points due east. (a) The magnit ude of the resultant displacement A + B is 5.38 km. What is the magnitude (in m) of B?
2 answers:
Answer:
B = 4325 m
Explanation:
Resolving the displacement into x and y components.
Let north = positive y component
East = positive x component
So,
Rx = B
Ry = -3.20 km
Magnitude of the resultant displacement is
R = √(B^2 + (-3.20)^2)
R is given as R = 5.38 km
Making B the subject of formula;
B = √(R^2 - (-3.20)^2)
B = √(5.38^2 - (-3.20)^2)
B = 4.325 km
B = 4325 m
Answer: 4,438.96m
Explanation:
(kindly find attachment below)
From the attachment below, it can be seen that the resultant displacement and the other 2 displacements form a right angle triangle, with A+B as the hypotenus, 3.2km as the opposite and the displacement B as the adjacent.
By using phythagoras theorem
H² = O² + A²
(5.38)² = (3.20)² + B²
28.944 = 10.24 + B²
B² = 28.944 - 10.24
B² = 18.7044
B = √18.7044
B = 4.439km to meter is 4.439 * 1000 = 4,438. 96m
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