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loris [4]
3 years ago
12

What is the first step in balancing a redox reaction by the half-reaction method?

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
7 0
First step is to balance the amount of atoms on each side

So for example if my equation that I have to balance is : Br2 -> Br-

First thing I would have to do would be :
Br2 -> 2Br-

Then I would have to balance the charges on both sides. So because there is a -2 charge on the right side I will have to add a -2 charge onto the right side as well. I would do this by :
Br2 + 2e- -> 2Br-

And now you can see the amount of atoms and the charges are balanced... So your overall reaction is now balanced too.
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URGENT! Consider the following decomposition reaction of ammonium carbonate ((NH4)2CO3):
dexar [7]
<span>Using PV=nRT to find the moles and then convert back.
</span><span>4x=.8944
</span><span>solve for x then use the pressure for lets say CO2 put that into PV=nRT then solve for n then convert over.
</span>
<span>(.2236)(2)/(298*.08206) = .0183*96g/mol = 1.76g
</span>
<span>For C:

[NH3]^2[CO2][H2O] = Kp
x=0.2236 (2*.2236)^2(.2236)*(.2236)
  =0.001
</span>
6 0
3 years ago
Calculate the % Oxygen in NaHCO3
Alexxx [7]

Answer:

Molar mass of NaHCO3 = 84.00661 g/mo

Explanation:

This compound is also known as Baking Soda or Sodium Bicarbonate.

Convert grams NaHCO3 to moles  or  moles NaHCO3 to grams

Molecular weight calculation:

22.98977 + 1.00794 + 12.0107 + 15.9994*3

3 0
3 years ago
An exothermic reaction occurs spontaneously ,why?​
Delvig [45]

Answer:

See below  

Step-by-step explanation:

An exothermic reaction tends to occur spontaneously because the products are more stable than the reactants.

Nature tries to get to the lowest energy state.

4 0
3 years ago
Consider the reaction H2(g) + I2(g) &lt;---&gt; HI(g) with an equilibrium constant of 46.3 and a reaction quotient of 525. Which
WARRIOR [948]

Answer:

The equilibrium will shift to the left to favor the reactants.

Explanation:

Remember that the reaction quotient (Qc) is derived from initial concentrations of reactants and products. Since Qc is greater than Kc, this means that initial concentrations are heavily impacted by a high product concentration ([HI]). Therefore, the reverse reaction will occur and actually create more reactants again ([H2] and [I2]). Thus, the answer is that the equilibrium will shift to the left side to favor the reactants.

8 0
3 years ago
Read 2 more answers
Could someone explain what oxidation numbers are and what these questions are asking of me?
Oxana [17]

The oxidation state, sometimes referred to as oxidation number, describes the degree of oxidation of an atom in a chemical compound.

<u>Explanation:</u>

The oxidation number of an atom is the charge that atom would have if the compound was composed of ions. 1. The oxidation number of an atom is zero in a neutral substance that contains atoms of only one element. The oxidation number of simple ions is equal to the charge on the ion.

The oxidation number of a mono atomic ion equals the charge of the ion. The oxidation number of H is +1, but it is -1 in when combined with less electro negative elements. The oxidation number of O in compounds is usually -2, but it is -1 in peroxides. The oxidation number of a Group 1 element in a compound is +1.

6 0
3 years ago
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