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Lisa [10]
4 years ago
10

Because of hydrogen bonding, which of the following characteristics are seen in water? A. Liquid water is denser than ice. B. Ic

e floats on top of liquid water. C. Ice sinks to the bottom of a lake. D. Liquid water is less dense than ice.
Physics
2 answers:
otez555 [7]4 years ago
8 0
B) Ice floats on top of liquid water and D) liquid is less dense than ice. The rest of the answers aren’t true because ice never sinks to the bottom of the water since ice is more dense than water.
Harman [31]4 years ago
5 0

Answer: A. Liquid water is denser than ice.

B. Ice floats on top of liquid water.

Explanation:

Water molecules are bonded by strong hydrogen bonding between the hydrogen atom and the electronegative oxygen atom.

The density of water is liquid state is more than the density of ice. Water has a property to expand when it freezes and it forms cage like structure in the ice. This results in the increase of volume and thus the density of ice is lesser than that of liquid water.

The substance with more density than water sinks in it and the substance with lesser density than water will float in water.

Thus ice being less dense than liquid water floats on top of it.

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Two solenoids A and B, spaced close to each other and sharing the same cylindrical axis, have 430 and 610 turns, respectively. A
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Answer

given,

Two solenoids A and B

Number of turn

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Current = 2.80 A

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a) L = \dfrac{N \phi}{I}

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   L =19.6 mH

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   L = \dfrac{N_A \phi_A}{I_A}

   L = \dfrac{430\times 300 \times 10^{-6}}{2.80}

   L =46 mH

c) magnitude of the emf

    \epsilon_B = -L_B\dfrac{dI}{dT}

    \epsilon_B = -(19.6\times 10^{-3})(0.5)

    \epsilon_B = -9.8\times 10^{-3}\ V

    \epsilon_B = -9.8\ mV

7 0
3 years ago
In the combo circuit diagrammed, R1 = 19.2 Ω, R2 = 20.7 Ω, and R3 = 25.8 Ω. Find the equivalent resistance of the circuit.
garik1379 [7]

Answer:

Equivalent resistance: 13.589 Ω

Explanation:

R series = R1 + R2 + R3 ...

\frac{1}{R_{eq} } = \frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} ...

Find the equivalent resistance of the right branch of the circuit:

R_{eq}  = R_{2} +R_{3} \\R_{eq} = 20.7 + 25.8 = 46.5 ohms

\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411

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