How many grams of aluminum sulfide would form if 2.25 liters of a 1.50 molar aluminum chloride solution reacts with 2.00 liters
of a 2.75 molar hydrosulfuric acid (H2S) solution? 2AlCl3 + 3H2S yields Al2S3 + 6HCl
a.18.6 g
b.101 g
c.253 g
d.275 g
a.18.6 g
b.101 g
c.253 g
d.275 g
1 answer:
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Answer : The vapor pressure of bromine at is 0.1448 atm.
Explanation :
The Clausius- Clapeyron equation is :
where,
= vapor pressure of bromine at
= ?
= vapor pressure of propane at normal boiling point = 1 atm
= temperature of propane =
= normal boiling point of bromine =
= heat of vaporization = 30.91 kJ/mole = 30910 J/mole
R = universal constant = 8.314 J/K.mole
Now put all the given values in the above formula, we get:
Hence, the vapor pressure of bromine at is 0.1448 atm.