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aleksandrvk [35]

3 years ago

13

How many grams of aluminum sulfide would form if 2.25 liters of a 1.50 molar aluminum chloride solution reacts with 2.00 liters

of a 2.75 molar hydrosulfuric acid (H2S) solution? 2AlCl3 + 3H2S yields Al2S3 + 6HCl
a.18.6 g
b.101 g
c.253 g
d.275 g

1 answer:

Alex787 [66]3 years ago

8 0

Hope this helps you!

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The term for free electrons in metals transferring energy by colliding with other atoms or electrons is _____.

shepuryov [24]

Conduction

In metals, the electrons of each atom are delocalized, which means they are free to move about in the structure of the metal. When heat is applied at one end of the metal, the electrons there are excited and collide with surrounding particles, transferring their energy to them. This is what makes metals very good conductors of both heat and electricity.

4 0

3 years ago

Read 2 more answers

Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu

ad-work [718]

Initial volume of the balloon = $V_{1}$ = 348 mL

Initial temperature of the balloon $T_{1}$ = $25.0^{0}C + 273 = 298 K$

Final volume of the balloon $V_{2}$ = 322 mL

Final temperature of the balloon = $T_{2} = ?$

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

$\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }$

On plugging in the values,

$\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }$

$T_{2} =276 K$

Therefore, the temperature of the freezer is 276 K

5 0

2 years ago

Help please I am so lost my teacher is no help

uranmaximum [27]

Answer:

B - CALCIUM

Explanation:

Hopes it helps

6 0

2 years ago

How many mL of 2M stock solution would I use to prepare 0.500 L of 0.1 M NaCl?

nordsb [41]

Answer:

25 mL

Explanation:

Step 1: Given data

Concentration of the concentrated solution (C₁): 2 M

Volume of the concentrated solution (V₁): ?

Concentration of the diluted solution (C₂): 0.1 M

Volume of the diluted solution (V₂): 0.500 L

Step 2: Calculate the volume of the concentrated NaCl solution

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.1 M × 0.500 L / 2 M

V₁ = 0.025 L = 25 mL

4 0

2 years ago

Pls answer these and show work

Assoli18 [71]

There's no question??

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8 0

2 years ago