How many grams of aluminum sulfide would form if 2.25 liters of a 1.50 molar aluminum chloride solution reacts with 2.00 liters
of a 2.75 molar hydrosulfuric acid (H2S) solution? 2AlCl3 + 3H2S yields Al2S3 + 6HCl
a.18.6 g
b.101 g
c.253 g
d.275 g
a.18.6 g
b.101 g
c.253 g
d.275 g
1 answer:
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Answer:
Explanation:
We are asked to find the mass of a number of platinum (Pt) atoms.
<h3>1. Convert Atoms to Moles </h3>First, we convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are platinum atoms.
We will convert using dimensional analysis so we set up a ratio using the information we know (6.022 × 10²³ platinum atoms in 1 mole of platinum).
We are converting 4.99 ×10²¹ atoms of Pt to moles of Pt, so we multiply by this value.
Flip the ratio so the units of atoms of platinum cancel.
Divide.
Next, we convert moles to grams using the molar mass. This is the mass of 1 mole of a substance. This is found on the Periodic Table because it is equivalent to the atomic mass, but the units are grams per mole instead of atomic mass units. Look up platinum's molar mass.
- Pt: 195.08 g/mol
Set up another ratio using this new information (195.08 grams of Pt in 1 mole of Pt).
Multiply by the number of moles we just calculated.
The units of moles of platinum cancel.
The original measurement of atoms ( 4.99 ×10²¹ ) has 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 6 in the thousandth place tells us to round the 1 up to a 2.
There are approximately <u>1.62 grams of platinum</u> in 4.99 ×10²¹ atoms of platinum.
