Technical Drawings give a better understanding of what is needed and required in the project.
Explanation:
Answer:
capacity = 0.555 mAh
capacity = 3600 mAh
Explanation:
given data
battery = 1800 mAh
OCV = 3.9 V
solution
we get here capacity when it is in series
so here Q = 2C
capacity = 2 × ampere × second ...............1
put here value and we get
and 1 Ah = 3600 C
capacity =
capacity = 0.555 mAh
and
when it is in parallel than capacity will be
capacity = Q1 +Q2 ...............2
capacity = 1800 + 1800
capacity = 3600 mAh
Answer:
0, 1, 2, 3, 6, 11, 20, 37, 68
Explanation:
Each number in the series, starting with 3, is the total of the three numbers before it. The following number is the total of the preceding three numbers, according to the pattern. The pattern's next number is 125.
Answer:
The inductance of the inductor is 0.051H
Explanation:
From Ohm's law;
V = IR .................. 1
The inductor has its internal resistance referred to as the inductive reactance, X, which is the resistance to the flow of current through the inductor.
From equation 1;
V = IX
X = ................ 2
Given that; V = 240V, f = 50Hz, = , I = 15A, so that;
From equation 2,
X=
= 16Ω
To determine the inductance of the inductor,
X = 2fL
L =
=
= 0.05091
The inductance of the inductor is 0.051H.