All categories

3 years ago

Hybrid orbitals of the sp3d type occur in sets of four. True or False?

Chemistry

1 answer:

lara31 [8.8K]3 years ago

3 0

well , it's true because they are of sp3d type occur on sets of four

You might be interested in

A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an

mr_godi [17]

Answer : The value of equilibrium constant (K) is, 424.3

Explanation : Given,

Concentration of $H_2$ at equilibrium = 0.067 mol

Concentration of $CO$ at equilibrium = 0.021 mol

Concentration of $CH_3OH$ at equilibrium = 0.040 mol

The given chemical reaction is:

$CO+2H_2\rightarrow CH_3OH$

The expression for equilibrium constant is:

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

Now put all the given values in this expression, we get:

$K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}$

$K_c=424.3$

Thus, the value of equilibrium constant (K) is, 424.3

4 0

3 years ago

SOME ONE HELP I FORGOT PIC!!! 20 POINTS AND BRAINLIEST!!!

stiks02 [169]

spindle fibers

i think the next is two nuclei and still together but that stage is not anaphase. Anaphase is when the sister chromatids are pulled apart

8 0

3 years ago

Read 2 more answers

Which element is present in all organic compounds?

Mkey [24]

The anser is 1, carbon

5 0

3 years ago

Read 2 more answers

Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)

Natali [406]

Answer:

a) 1.44g

b) 77.3%

Explanation:

1. Chemical balanced equation (given)

$NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)$

2. Mole ratio

$1molNaOH(aq):1molKHP(s)$

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

3. Find the number of moles in 72.14 mL of the base

$Molarity=\text{number of moles of solute}/\text{volume of solution in liters}$

$\text{Volume of solution}=72.14mL=0.07214liters$

$\text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol$

4. Find the number of grams of KHP that reacted

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

mass = number moles × molar mass = 0.007055mol × 204.23g/mol

mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

5. Find the percentage of KHP in the sample

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

% = (mass of substance / mass of sample) × 100

% = (1.4408g/ 1.864g) × 100 = 77.3%

7 0

3 years ago

Can you do my project please and I'll mark brainllest

Alex17521 [72]

Answer:

Whats the project?

Explanation:

8 0

3 years ago