We will apply the concept of period in a pendulum, defined as the product between 2 $\pi$ by the square root of the length over gravity, this is mathematically

$T = 2\pi \sqrt{\frac{L}{g}}$

Here,

T = Period

L = Length

g = Acceleration due to gravity

For the period to be 1 second, then we must look for the necessary length for such a requirement so

$1 = 2\pi \sqrt{\frac{L}{9.8}}$

$(\frac{1}{2\pi})^2 = \frac{L}{9.8}$

$L = 9.8(\frac{1}{2\pi})^2$

$L = 0.2482m$

The meter's length would be slight less than one-fourth of its current length. Also, the number of significant digits depends only on how precisely we know g, because the time has been defined to be exactly 1s.

Therefore the correct answer is C.

3 0

3 years ago

If you poke a hole into a plastic bottle, and stick a straw in it, and then let the straw connect to a glass cup, and then blow

den301095 [7]

It was decrease because the water js going from one place to another

6 0

3 years ago

Watching television, with theremote control in your hand, which of the following exerts the greatest gravitational force on you?

natulia [17]

A. The couch you are sitting on

3 0

3 years ago

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