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kodGreya [7K]
3 years ago
13

A sample of helium gas in a balloon is compressed from 4.0 L to 3.2 L at a constant temperature. If the pressure of the gas in t

he 4.0 L volume is 229 kPa, what will the new pressure?
Chemistry
1 answer:
vampirchik [111]3 years ago
4 0

Answer:

286 kPa

Explanation:

Boyles law states that volume of gas is inversely proportional to pressure o gas for a fixed amount of gas at constant temperature

P1V1 = P2V2

where P1 is pressure and V1 is volume at first instance

P2 is pressure and V2 is volume at the second instance

substituting the values in the equation

229 kPa x 4.0 L = P2 x 3.2 L

P2 = 286.25 kPa

the new pressure is 286 kPa

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X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the volume of the gaseous mixture was 5.00 L. After the reaction, the volume
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Isobaric transition, first law: <span>H=ΔU+w</span> for a gas expansion: <span>w=<span>P<span>ext</span></span>∗ΔV</span> to convert to joules, you need the gas constants. R = 0.08206 L atm/mol*K, R=8.314 J/mol*K <span>w=<span>P<span>ext</span></span>∗ΔV∗<span><span>8.314 J/mol∗K</span><span>0.08206 L atm/mol∗K</span></span></span> <span>ΔU=ΔH−[<span>P<span>ext</span></span>∗ΔV∗<span><span>8.314 J/mol∗K</span><span>0.08206 L atm/mol∗K</span></span>]</span> <span>ΔU=−75000 J−[(43.0atm)∗(2−5)L∗<span><span>8.314 J</span><span>0.08206 L atm</span></span>]</span> Then you need to convert to kJ. by the way U=E, internal energy.
7 0
3 years ago
Consider the reaction below. HI + H2O mc014-1.jpg H3O+ + I– Which is an acid-conjugate base pair? HI and H2O H2O and H3O+ H3O+ a
lesya692 [45]

Answer: Option (d) is the correct answer.

Explanation:

According to Bronsted-Lowry, species which donate a proton are known as acid. The species which accept a proton are known as a base.

In the given reaction, acids and bases are as follows.

    HI  +   H_{2}O \rightarrow    H_{3}O^{+}           +         I^{-}

 Acid        Base     Conjugate acid   Conjugate base

Therefore, the acid HI loses a proton to form a conjugate base that is I^{-}.

Thus, we can conclude that HI and I^{-} is an acid conjugate base pair.

4 0
3 years ago
Read 2 more answers
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lesya692 [45]
The correct option is C.
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7 0
3 years ago
In k4[fe(cn)6], how many 3d electrons does the iron atom have?
san4es73 [151]
First let's find out the oxidation number of Fe in K₄[Fe(CN)₆] compound.

The oxidation number of cation, K is +1. Hence, the total charge of the anion, [Fe(CN)₆] is -4. CN has charge has -1. There are 6 CN in anion. Let's assume the oxidation number of Fe is 'a'.

Sum of the oxidation numbers of each element  = Charge of the compound
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Hence, oxidation number of Fe in [Fe(CN)₆]⁴⁻ is +2. 

Now Fe has the atomic number as 26. Hence, number of electrons in Fe at ground state is 26. 
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When making Fe²⁺, Fe releases 2 electrons. Hence, the number of electrons in Fe²⁺ is 26 - 2 = 24.
Hence, the electron configuration of Fe²⁺ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶
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Hence, the number of 3d electrons of Fe in K₄[Fe(CN)₆] compound is 6.
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3 years ago
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Hope this helps! (:
8 0
2 years ago
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