Answer:
W = 0.842 J
Explanation:
To solve this exercise we can use the relationship between work and kinetic energy
W = ΔK
In this case the kinetic energy at point A is zero since the system is stopped
W = K_f (1)
now let's use conservation of energy
starting point. Highest point A
Em₀ = U = m g h
Final point. Lowest point B
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
mg h = K
to find the height let's use trigonometry
at point A
cos 35 = x / L
x = L cos 35
so at the height is
h = L - L cos 35
h = L (1-cos 35)
we substitute
K = m g L (1 -cos 35)
we substitute in equation 1
W = m g L (1 -cos 35)
let's calculate
W = 0.500 9.8 0.950 (1 - cos 35)
W = 0.842 J
The correct answer is: They possess high concentrations of free electrons
The main characteristic of good conductors such as metals is the presence of movable electrically charged particles, or electrons. So, when an electric current is applied to a metal, the electrons will move and allow electricity to pass through them. Materials opposite of metals, with low electron mobility are not good conductors, instead they are called insulators.
Answer:
some one might report you
Explanation:
Explanation:
The given data is as follows.
Voltage = 2.50 V
Hence, calculate the equivalence capacitor as follows.
= 
C = 
Now, we will calculate the charge across each capacitance as follows.
Q = CV
= 
= 
= 
Thus, we can conclude that is the charge stored on each given capacitor.
Answer:
-0.04194 V
Explanation:
= Number of turns in outer solenoid = 330
= Number of turns in inner solenoid = 22
= Current in inner solenoid = 0.14 A
= Rate of change of current = 1800 A/s
= Vacuum permeability = 
r = Radius = 0.0115 m
Magnetic field is given by
The average magnetic flux through each turn of the inner solenoid is
Magnetic flux is given by
Mutual inductance is given by
The mutual inductance of the two solenoids is
Induced emf is given by
The emf induced in the outer solenoid by the changing current inthe inner solenoid is -0.04194 V
