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kumpel [21]
3 years ago
9

We go out to sunbathe on a warm summer day. If we soak up 80 British thermal units per hour​ [BTU/h] of​ energy, how much will t

he temperature of 65 comma 000​-gram person increase in 2 hours ​[h] in units of degrees Celsius​ [°C]? We assume that since our bodies are mostly water they have the same specific heat as water ​(4.18 joules per gram degree Celsius​ [J/(g degrees Upper C​)]).
Physics
1 answer:
Jlenok [28]3 years ago
7 0

Answer:

0.62127°C

Explanation:

1\ BTU=1055\ J

80\ BTU/h=80\times 1055=84400\ J/h

Heat absorbed by body in 2 hours

Q=84400\times 2\\\Rightarrow Q=168800\ J

m = Mass of person = 65000 g

c = Specific heat of water = 4180 J/kg°C

\Delta T = Change in temperature

Heat is given by

Q=mc\Delta T\\\Rightarrow 168800=65\times 4180\times \Delta T\\\Rightarrow \Delta T=\dfrac{168800}{65\times 4180}\\\Rightarrow \Delta T=0.62127\ ^{\circ}C

The increase in temperature will be 0.62127°C

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Explanation: Tsunami is described as several waves originating from a water body mainly an ocean caused by Large scale earth movements taking place under the sea.

Superimposition of wave is the movement of one wave on another,it can be constructive or destructive.

Constructive interference is a wave interference that take place causing the Crest of one wave to align with that of another wave leading to high amplitude.

Destructive interference is a wave interference that take place causing the Trouph of one wave to align with the crest of another wave leading to low amplitude wave.

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3 years ago
Calculate the missing angles in the following diagram if the index of refraction is 1.00
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4 years ago
Human reaction times are worsened by alcohol. How much further (in feet) would a drunk driver's car travel before he hits the br
sweet-ann [11.9K]

Answer:

A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes

Explanation:

Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

where,  

Vf = Final Velocity of Car = 0 mi/h

Vi = Initial Velocity of Car = 50 mi/h

a = deceleration of car  

s = distance covered

Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.

So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:

s = vt

FOR SOBER DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 0.33 s

s = s₁

Therefore,

s₁ = (73.33 ft/s)(0.33 s)

s₁ = 24.2 ft

FOR DRUNK DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 1 s

s = s₂

Therefore,

s₂ = (73.33 ft/s)(1 s)

s₂ = 73.33 ft

Now, the distance traveled by drunk driver's car further than sober driver's car is given by:

ΔS = s₂ - s₁

ΔS = 73.33 ft - 24.2 ft

<u>ΔS = 49.13 ft</u>

6 0
3 years ago
A 12.0-g bullet is fired horizontally into a 109-g wooden block that is initially at rest on a frictionless horizontal surface a
kykrilka [37]

Answer:

v₀ = 280.6 m / s

Explanation:

we have the shock between the bullet and the block that we can work with at the moment and another part where the assembly (bullet + block) compresses a spring, which we can work with mechanical energy,

We write the mechanical energy when the shock has passed the bodies

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We write the mechanical energy when the spring is in maximum compression

Em_{f} = K_{e} \\= \frac{1}{2} kx^2\\    Em_0 = Em_{f}

½ (m + M) v² = ½ k x²

Let's calculate the system speed

   v = √ [k x² / (m + M)]

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   v = 27.65 m / s

This is the speed of the bullet + Block system

Now let's use the moment to solve the shock

Before the crash

   p₀ = m v₀

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p_{f} = (m + M) v

The system is formed by the bullet and block assembly, so the forces during the crash are internal and the moment is preserved

 p_0 =  p_{f}

  m v₀ = (m + M) v

  v₀ = v (m + M) / m

let's calculate

v₀ = 27.83 (0.012 +0.109) /0.012

  v₀ = 280.6 m / s

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3 years ago
A sled is at rest at the top of a 2 m high slope. The sled has a mass of 45 kg. The sled's potential energy isJ. (Formula: PE =
elixir [45]
Data:

h = 2m
m = 45 Kg
PE = ? (Joule)

Adopting, gravity (g) ≈ <span>9,8 m/s² 
</span>
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Solving:

PE_{grav} = mass * g * height
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Answer:
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8 0
3 years ago
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