Question

An electron is located in an electric field of magnitude 600 Newton's per coulomb. What is the magnitude of the electrostatic force acting in the electron?

Answer 1

Answer:

The magnitude of the electrostatic force acting in the electron is $9.6\times 10^-^1^7N$.

Explanation:

The relation between electric field, electric force and charge is given as

$F=eE$

Here E is electric field, F is the electric force and e is the electric charge on electron.

Given $F=600N/C,\ e=-1.6\times10^-^1^9C$.

Substitute the given values, we get

$F=-1.6\times10^-^1^9C\times600N/C$

The magnitude of force,

$|F|=9.6\times10^-^1^7N$.

Thus, the magnitude of the electrostatic force acting in the electron is $9.6\times 10^-^1^7N$.

Answer 2

Answer:  

force on electron will be equal to $9.6\times 10^{-17}N$

Explanation:

We have given magnitude of electric field E = 600 N/C

Charge on electron $e=1.6\times 10^{-19}C$

We have to find the electric force on the electron

Force in electric field is equal to $F=qE$, here q is charge and E is electric field

So force will be equal to $F=1.6\times 10^{-19}\times 600=960\times 10^{-19}=9.6\times 10^{-17}N$

So force on electron will be equal to $9.6\times 10^{-17}N$