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3 years ago

Which species is a conjugate acid of OH-?

Chemistry

2 answers:

ra1l [238]3 years ago

6 0

Answer:

Water.

Explanation:

Hello,

In this case, you are referring to the dissociation or formation of water at the equilibrium, that is:

$H^++OH^-H_2O$

In such a way, the water is the conjugate acid of the hydroxile ion as long as it gains a proton.

Best regards.

lara31 [8.8K]3 years ago

3 0

It seems that you have missed the necessary options for this answer, but anyway, the answer for this would be H20. The specie that is a conjugate acid of OH- is H20. H20 is the conjugate acid and OH- is the conjugate base. Hope this answers your question. Have a great day!

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How many hydrogen atoms are contained in 167 grams of propane?

Dmitry_Shevchenko [17]

Propane is C3H8

So Molar mass propane = 3*12 + 8*1 = 44 <span>
No. of moles of propane = 167/44 = 3.795 moles</span>

From the stoichiometry: <span>
No. of moles of hydrogen = 3.795 moles * (8 moles hydrogen / 1 mole propane) = 30.36 moles

Using Avogadros number, 1 mole of any substance contains 6.022 x 10^23 atoms, therefore:
<span>No. of hydrogen atoms = 30.36 * 6.022 x 10^23 = 1.828 x 10^25 atoms</span></span>

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3 years ago

2.5kg weighing cat climbing at the top of the tree has a potential energy of 986 J. Find the height.

Kruka [31]

Answer:

The height = 39.44 m

Explanation:

Given:

Mass m = 2.5 kg

Potential energy = 986 J

Find:

The height

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Potential energy = mgh

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986 = (2.5)(10)(h)

h = 39.44 m

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3 years ago

How many liters of 1.2M solution can be prepared with 0.50 moles of C6H12O6

BigorU [14]

First you need to know the molecular weight of sugar (C6H12O6) which is 180.156g/mol
You have half a mole so you have 90.078g
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But you only have 90.078g
So you need to figure out how much this 90.078g will make if the solution must be 1.2M:
90.078g/216.1872g=xL/1L
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3 years ago

Someone please help me figure this out!!

zavuch27 [327]

Answer: from what i can tell it looks like a heterogeneous mixture

Explanation:

heterogeneous is multiple different components, homogenous includes only the same component

7 0

3 years ago

formic acid buffer containing 0.50 M HCOOH and 0.50 M HCOONa has a pH of 3.77. What will the pH be after 0.010 mol of NaOH has b

HACTEHA [7]

Answer:

pH = 3.95

Explanation:

It is possible to calculate the pH of a buffer using H-H equation.

pH = pka + log₁₀ [HCOONa] / [HCOOH]

If concentration of [HCOONa] = [HCOOH] = 0.50M and pH = 3.77:

3.77 = pka + log₁₀ [0.50] / [0.50]

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Knowing pKa, the NaOH reacts with HCOOH, thus:

HCOOH + NaOH → HCOONa + H₂O

That means the NaOH you add reacts with HCOOH producing more HCOONa.

Initial moles of 100.0mL = 0.1000L:

[HCOOH] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOOH

[HCOONa] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOONa

After the reaction, moles of each species is:

0.0500moles HCOOH - 0.010 moles NaOH (Moles added of NaOH) = 0.0400 moles HCOOH

0.0500moles HCOONa + 0.010 moles NaOH (Moles added of NaOH) = 0.0600 moles HCOONa

With these moles of the buffer, you can calculate pH:

pH = 3.77 + log₁₀ [0.0600] / [0.0400]

3 0

3 years ago