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Dmitry [639]
4 years ago
7

A race car accelerates from rest to a velocity of +90 m/s over a distance of 423m. Determine the acceleration of the race car.

Physics
1 answer:
dlinn [17]4 years ago
4 0

Answer:

9.57m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 90m/s

Distance  = 423m

Unknown:

Acceleration of the race car  = ?

Solution:

To solve this problem, we should apply one of the appropriate motion equations;

      V²  = U²   + 2as

Where V is the final velocity

           U is the initial velocity

           a is the acceleration

           s is the distance

  90²  = 0²  + 2 x a x 423

  8100 = 846a

      a  = 9.57m/s²

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A cyclotron is designed to accelerate protons (mass 1.67 x 10^-27 kg) up to a kinetic energy of 2.5 x 10^-13 J. If the magnetic
Dafna11 [192]

Answer:

24 cm

Explanation:

Given:

Mass of proton = 1.67 × 10⁻²⁷ Kg

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Now,

Kinetic energy = \frac{1}{2}mv^2  = 2.5 × 10⁻¹³ J

where, v is the velocity of the electron

or

\frac{1}{2}\times1.67\times10^{-27}\times v^2  = 2.5 × 10⁻¹³ J

or

v² = 2.99 × 10¹⁴

or

v = 1.73 × 10⁷ m/s

also,

centripetal force = magnetic force

or

\frac{mv^2}{r}  = qvB

q is the charge of the electron

r is the radius of the dipole magnets

on substituting the respective values, we get

\frac{1.67\times10^{-27}\times1.73\times10^7}{r}  = 1.6 × 10⁻¹⁹ × 0.75

or

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Hence, the correct answer is 24 cm

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