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Naily [24]
3 years ago
8

Consider the balanced equation

Chemistry
2 answers:
11111nata11111 [884]3 years ago
7 0

Answer : The mole ratio of NH_3 to N_2 is, 4 : 2

Explanation :

Mole ratio : It is defined as the ratio of number of moles of the substances whose ratio is to be calculated.

The given balanced chemical reaction is :

4NH_3+3O_2\rightarrow 2N_2+6H_2O

By stoichiometry of the reaction we can say that,

4 moles of ammonia reacts with the 3 moles of oxygen to produce 2 moles of nitrogen and 6 moles of water.

Hence, the mole ratio of NH_3 to N_2 is, 4 : 2

Naya [18.7K]3 years ago
6 0
4:2. You are comparing the coefficients of NH3 and N2
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Is the following chemical equation balanced?
FrozenT [24]

Answer:

No

Explanation:

The given equation is not balanced

Chemical equation:

KClO₄ → KCl + O₂

Given Balanced chemical equation:

KClO₄ → 2KCl + 2O₂

Correctly balanced chemical equation:

2KClO₄ → 2KCl + 4O₂

Now this equation is correctly balanced.

There are two potassium atom two chlorine atoms and eight oxygen atoms on both side of equation. So this is correctly balanced.

Coefficient with reactant and product:

KClO₄    2

KCl        2

O₂         4

5 0
4 years ago
An ionic compound has a solubility of 30 g per 100 mL of water at room temperature. A solution containing 70 g of the compound i
Llana [10]

Answer: A. unsaturated.

Explanation:

Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

Supersaturated solution is defined as the solution in which more amount of solute particles is present than the solvent particles.

Given:  Solubility = 30g/100ml

If 100 ml can dissolve ionic compound = 30 g

300 ml can dissolve ionic compound  =\frac{30}{100}\times 300=90g

Thus solubility is 90g/300 ml and dissolved salt is only 70 g , the solution is said to be unsaturated.

3 0
3 years ago
A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,
agasfer [191]

Answer:The answer is C on edge!

Explanation:

4 0
3 years ago
Read 2 more answers
To prepare a solution of BF4-(aq), HF(g) is bubbled into a solution containing 50.0 g of H3BO3 in a 1 L reaction vessel. Calcula
Fudgin [204]

Answer:

Explanation:

The chemical reaction involved is as follows

H₃BO₃ + 4HF = HBF₄ + 3H₂O

1 mol                  1 mol

mol weight of H₃BO₃ is 61.84 gm

50g = 50 / 61.84 mol.

= 0.8 mol.

.8 mol of H₃BO₃ will form .8 mol of BF₄⁻ ion .

6 0
4 years ago
Identify your unknowns and use your experimental evidence to support your identification
Masteriza [31]
<span>During an experiment, given that other elements that make up the compound are identified, an unknown element x can easily make separate if certain properties of that unknown element is exhibited in the experiment. So, the first thing to do would be to identify the compound, identify and isolate all the knowns and one can test to see the properties which the unknown element is giving and make a reasonable deduction from that.For example if we were testing for the presence of water in Copper(II) sulfate . if water is in the sample that we were testing for, we will see that the sample will turn blue because of the presence of water</span>
3 0
3 years ago
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