Explanation:
<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>directly</em><em> </em><em>proportional</em><em>, </em><em>because</em><em> </em><em>when</em><em> </em><em>there</em><em> </em><em>is</em><em> </em><em>more</em><em> </em><em>concentration</em><em> </em><em>their</em><em> </em><em>will</em><em> </em><em>more</em><em> </em><em>reactants</em><em> </em><em>to</em><em> </em><em>react</em><em> </em><em>fast</em><em> </em><em>diring</em><em> </em><em>the</em><em> </em><em>chemical</em><em> </em><em>reaction</em><em> </em><em>which</em><em> </em><em>increases</em><em> </em><em>the</em><em> </em><em>rate</em><em> </em><em>of</em><em> </em><em>chemical</em><em> </em><em>reaction</em><em>. </em>
<em>So</em><em>,</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>state</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>relationship</em><em> </em><em>between</em><em> </em><em>them</em><em> </em><em>are</em><em> </em><em>directly</em><em> </em><em>proportional</em><em>. </em>
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Carbohydrates are classified in three major categories depending upon the number of sub units joining to form them. These are,
Monosaccharides
Oligosaccharides
Polysachharides
The simplest single units are monosaccharides, if units are ranging between two and twenty they are called oligosaccharides and above twenty joining units they are called polysachharides.
Result:
<span>The proper name for a carbohydrate polymer with 2 subunits is called Oligosachharide in general and Disaccharide in specific.</span>
Answer:
if you will decrease the HCO3- so the less H+ ion will be form and reaction will more likely shift to product and when HCO3- decreases pH value increases and vica versa for the increasing HCO3 the more H+ ion will be form and reaction will shift to product and the pH value will decreases!!
I've doubt in reaction shift coz whatever is the amount of HCO3- this is completely gonna form number of H+ so reaction shift may or may not be same!!
The combustion of 1 mole of methane (CH4) in a domestic furnace requires 2 moles of O2 molecules, assuming the combustion was complete or ideal. To solve this problem, use stoichiometry of the reaction's balanced chemical equation:
CH4 + 2O2 --> CO2 + 2H2O
The ratio of CH4 to O2 in terms of moles is 1:2. So 1 mole of CH4 needs 2 moles of O2.
