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algol13
3 years ago
14

Microbial food infections are usually not seen until ______ after eating contaminated food.

Physics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

2 to 4 hours

Explanation:

Given that,

Microbial food infections

We know that,

Food infection :

When we eat old food, uncooked, fermented food, more junk food and contaminated food then 2 to 4 hours after eating we started vomiting, headache then we affected by food infections.

So, we can say that microbial food infections are usually not seen until 2 to 4 hours after eating contaminated food.

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Which of the following effects results from the interference of two sound
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Answer:beats

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3 years ago
What is the change in electric potential energy in moving an electron from a location 3 × 10-10 m from a proton to a location 7
joja [24]

Answer:

4.39 x 10^-19 J

Explanation:

q1 = 1.6 x 10^-19 C

q2 = - 1.6 x 10^-19 C

r1 = 3 x 10^-10 m

r2 = 7 x 10^-10 m

The formula for the potential energy is given by

U1 = k q1 q2 / r1 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (3 x 10^-10)

U1 = - 7.68 x 10^-19 J

U2 = k q1 q2 / r2 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (7 x 10^-10)

U2 = - 3.29 x 10^-19 J

Change in potential energy is

U2 - U1 = - 3.29 x 10^-19 + 7.68 x 10^-19 = 4.39 x 10^-19 J

5 0
4 years ago
Average velocity is different than average speed because calculating average velocity involves
ANTONII [103]

Average velocity is different than average speed because calculating average velocity involves  considering the direction the bodies are moving.

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6 0
3 years ago
Read 2 more answers
7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The m
Nesterboy [21]

Answer:

3.34 kJ

Explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

n=\frac{m }{M_m}

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m = 10.0 g is the mass

Substituting

n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol

Now we know that the heat of fusion is

H_{fus}=6.01 kJ/mol

so the thermal energy needed to fuse the ice is

Q=n H_{fus} = (0.555 mol)(6.01 kJ/mol)=3.34 kJ

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3 years ago
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