The orbital period is proportional to r^(3/2) and does not depend on the satellite's mass. Any object at Jupiter's position will have the same orbital period regardless of mass. The correct answer is 11.9 yr. <u>Option C.</u>
As the Earth rotates on its axis creating day and night, it travels around the Sun in an elliptical orbit taking about 365 1/4 days to complete. The Earth's rotation axis is tilted with respect to the orbital plane. This creates seasons. The elliptical nature of the Earth's orbit is due to the first forces pushing the Earth away from the Sun's disk.
The momentum of this throw being greater the Earth's orbit would have been more elliptical or it might have been completely ejected from the solar system forever. The Earth's orbit defines a two-dimensional plane called the Ecliptic. It takes about 365 days for the earth to revolve around the sun. After years of analysis, Kepler found that Mars' orbit was likely elliptical, with the Sun at one of his focal points of the ellipse. This led Kepler to discover that all planets orbit the Sun in elliptical orbits and that the Sun is at one of his two focal points.
Learn more about The mass here:-brainly.com/question/26150306
#SPJ4
Answer: Polar Easterlies
Explanation: Winds flow from high pressure areas to low pressure areas. They originate in the north and south pole creating high pressure zones which generates an outflow. This outflow is then directed from east to west and hence the term used to describe these winds is Polar Easterlies.
Answer:
First, precipitate of AgCl is formed. Second, a soluble complex of silver and ammonia is formed. Third, AgCl is reproduced due to disappearance of ammonia complex in presence of 
.
Explanation:
In presence of NaCl, 
forms an insoluble precipitate of AgCl.
Reaction: 
In presence of 
, AgCl gets dissolved into solution due to formation of soluble ![[Ag(NH_{3})_{2}]^{+}](https://tex.z-dn.net/?f=%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%5E%7B%2B%7D)
complex.
Reaction: ![AgCl(s)+2NH_{3}(aq.)\rightarrow [Ag(NH_{3})_{2}]^{+}(aq.)+ Cl^{-}(aq.)](https://tex.z-dn.net/?f=AgCl%28s%29%2B2NH_%7B3%7D%28aq.%29%5Crightarrow%20%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%5E%7B%2B%7D%28aq.%29%2B%20Cl%5E%7B-%7D%28aq.%29)
In presence of , complex gets destroyed and free 
again reacts with free 
to produce insoluble AgCl
Reaction: ![[Ag(NH_{3})_{2}]^{+}(aq.)+2H^{+}(aq.)+Cl^{-}(aq.)\rightarrow AgCl(s)+2NH_{4}^{+}(aq.)](https://tex.z-dn.net/?f=%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%5E%7B%2B%7D%28aq.%29%2B2H%5E%7B%2B%7D%28aq.%29%2BCl%5E%7B-%7D%28aq.%29%5Crightarrow%20AgCl%28s%29%2B2NH_%7B4%7D%5E%7B%2B%7D%28aq.%29)
Answer:
Thus, the order of the reaction is 2.
The rate constant of the graph which is :- 2.00 M⁻¹s⁻¹
Explanation:
The kinetics of a reaction can be known graphically by plotting the concentration vs time experimental data on a sheet of graph.
The concentration vs time graph of zero order reactions is linear with negative slope.
The concentration vs time graph for a first order reactions is a exponential curve. For first order kinetics the graph between the natural logarithm of the concentration vs time comes out to be a straight graph with negative slope.
The concentration vs time graph for a second order reaction is a hyberbolic curve. Also, for second order kinetics the graph between the reciprocal of the concentration vs time comes out to be a straight graph with positive slope.
Considering the question,
A plot of 1/[NOBr] vs time give a straight line with a slope of 2.00 M⁻¹s⁻¹.
<u>Thus, the order of the reaction is 2.</u>
<u>Also, slope is the rate constant of the graph which is :- 2.00 M⁻¹s⁻¹</u>
