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sdas [7]
3 years ago
15

Can someone help me please

Physics
2 answers:
lions [1.4K]3 years ago
4 0
C is the answer. Hope i could help.
SCORPION-xisa [38]3 years ago
4 0
(c)is the answer. I think
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A small asteroid with a mass of 1500 kg moves near the earth. At a particular instant the asteroid’s velocity is ⟨3.5 × 104, −1.
zalisa [80]

Answer:

P_{f} =(5.7 x 10^{7 i - 2.24 x 10^{7 j) kgm/s

Explanation:

Due to earths gravity, force on asteroid is given by:

F= \frac{Gm_{1}m_{2} }{r^{2} } r^

Plugging in the values, we have

F= [(6.67x10^{-11})(1500)(5.97 x 10^{24})(8x10^{6}i + 9x10^{6 j)] / ((8x10^{6})² + (9x10^{6 )²)^{1.5}

F= 2736 i^ + 3078 j^

In order find the final momentum of the Asteroid, apply impulse momentum theorem

P_{f} = P_{i + FΔt

P_{f} = 1500(3.5 x 10^{4 i - 1.8x10^{4 j) + (2736i + 3078j)(1.5x10^{3)

P_{f} =(5.7 x 10^{7  i- 2.24 x 10^{7 j)kgm/s

4 0
4 years ago
1.A car starts from rest and acquires a velocity of 54 km/h in 2 minutes.Find(i) the acceleration and(ii) distance travelled by
Sergeu [11.5K]

Answer:

1.) 1620 km/h^2

2.) 2.7 km

Explanation:

1.) Given that the car start from rest. The initial velocity U will be equal to zero. That is,

U = 0.

Final velocity V = 54 km/h

Time t = 2 minute = 2/60 = 1/30 hour

Acceleration a will be change in velocity per time taken. That is,

a = ( V - U )/ t

Substitute V, U and t into the formula

a = 54 ÷ 1/30

a = 54 × 30 = 1620 km/h ^2

2.) Distance travelled S by the car during the time can be calculated by using the 2nd equation of motion.

S = Ut + 1/2at^2

Substitute all the parameters into the formula

S = 54 × 1/30 + 1/2 × 1620 × (1/30)^2

S = 54/30 + 810 × 1/900

S = 54/30 + 810/900

S = (1620+810)/900

S = 2430/900

S = 2.7 km.

Therefore, distance travelled by the car during this time is 2.7 km

4 0
3 years ago
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