Explanation:
Refer the given figure showing the arrangement.
For having stability we have torque at A and B are zero.
Sum of Torques at A = 0
700 x 1 + 200 x 1.5 - Q x 3 = 0
3Q = 1000
Q = 333.33 N
Sum of Torques at B = 0
200 x 1.5 + 700 x 2 - P x 3 = 0
3P = 1700
P = 566.67 N
Tension in ropes are 333.33 N and 566.67 N.
B) are compressible.
gasses are compressible