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Aliun [14]
4 years ago
5

A window washer is standing on a scaffold supported by vertical ropes at each end. The scaffold weighs 200. N and is 3.00 m long

. What is the tension in each rope when the 700. N worker stands 1.00 m from one end?

Physics
1 answer:
seropon [69]4 years ago
5 0
<h2>Tension in ropes are 333.33 N and 566.67 N.</h2>

Explanation:

Refer the given figure showing the arrangement.

For having stability we have torque at A and B are zero.

        Sum of Torques at A = 0

        700 x 1 + 200 x 1.5 - Q x 3 = 0

                               3Q = 1000

                                  Q = 333.33 N

        Sum of Torques at B = 0

        200 x 1.5 + 700 x 2 - P x 3 = 0

                               3P = 1700

                                  P = 566.67 N  

Tension in ropes are 333.33 N and 566.67 N.

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A car whose total mass is 800kg travelling with a uniform velocity of 20m/s suddenly observes a stationary dog 50m ahead on its
maxonik [38]

Answer:

The driver hits the stationery dog because the applied force is less than required force

Explanation:

Kinetic energy will be given by

KE=0.5mv^{2} where m is the mass of the vehicle and v is the speed/velocity of the vehicle.

Substituting 800 Kg for m and 20 m/s for v we obtain

KE=0.5*800*(20 m/s)^{2}=160,000

Frictional force by vehicle pads is given by

Fr=\frac {KE}{d} where d is the distance moved

Substituting 160000 for KE and 50 m for d we obtain

Fr=\frac {160000}{50}=3200 N

Therefore, the vehicle hits the dog since the required force is 3200N but the driver applied only 2000 N

7 0
3 years ago
Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;
nikdorinn [45]

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

P=60+100\\P=160 [W]

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

P=V*I

where:

P = power [W]

V = voltage [V]

I = current [amp]

I = P/V\\I=160/240\\I=0.67 [amp]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

V=I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R

60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

R = 133.66 + 225\\R = 358.67 [ohms]

7 0
3 years ago
Solve this question with steps
Novay_Z [31]
The problem was too big to type in my phone.

I hope my answer is readable.

P.S After the collision P is also moving in the same direction as Q.

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4 years ago
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bagirrra123 [75]

Answer:

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Explanation:

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Answer:

1e , 2j , 3c , 4d , 5k , 6a , 7i , 8b , 9m , 10h ,11g , 12f , 13l .

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