A person is submerged of about 97.9%.
The average density of the human body is given as 979 kg/ m³.
<h3>Define Law of floatation.</h3>
Law of floatation can be defined as the volume of the liquid displaced when a body floats on the liquid surface is equal to the body submerged in the water.
As body has the stable equilibrium state, the buoyancy of the fluid will be equal to the weight.
Weight of the body floating = Weight of the body immersed in fluid
Law of floatation = Density of the floating object / density of fluid
As fluid is the freshwater here, the density of fluid will be 1000 kg/ m³.
= (979 kg/ m³) / ( 1000 kg/ m³)
= 97.9 %
A person is submerged when floating gently in fresh water about 97.9%.
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Answer:
Distance-how far smthing travels.
Explanation:
That is correct what you did
1. The problem statement, all variables and given/known data A person jumps from the roof of a house 3.4 meters high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.70 meters. If the mass of his torso (excluding legs) is 41 kg. A. Find his velocity just before his feet strike the ground. B. Find the average force exerted on his torso by his legs during deceleration. 2. Relevant equations I can't even seem to figure that part out. Help please? 3. The attempt at a solution I don't know how to start this at all
Answer:
1.11 x 10^6 m
Explanation:
mass of Pluto, M = 1.1 x 10^22 kg
acceleration due to gravity on Pluto, g = 0.59 m/s²
let R be the radius of the Pluto and G is the universal gravitational constant.
G = 6.67 x 10^-11 Nm²/kg²
use the formula for the acceleration due to gravity
R = 1.11 x 10^6 m
Thus, the radius of the Pluto is 1.11 x 10^6 m.