Answer:
The induced current is 0.084 A
Explanation:
the area given by the exercise is
A = 200 cm^2 = 200x10^-4 m^2
R = 5 Ω
N = 7 turns
The formula of the emf induced according to Faraday's law is equal to:
ε = (-N * dφ)/dt = (N*(b2-b1)*A)/dt
Replacing values:
ε = (7*(38 - 14) * (200x10^-4))/8x10^-3 = 0.42 V
the induced current is equal to:
I = ε /R = 0.42/5 = 0.084 A
Characteristics help us to classify seeds because different plants have different features.
<h3>How are characteristics used to identify and classify plants?</h3>
The divisions classify plants that are based on whether they reproduce by spores or seeds. Spore-bearing plants include ferns, club mosses, and horsetail while on the other hand, Seed-bearing plants are divided into gymnosperms and angiosperms. Different plants have different characteristics and features so on the basis of these characteristics we can easily classify seeds whether they belong from angiosperm and gymnosperm.
So we can conclude that characteristics help us to classify seeds because different plants have different features.
Learn more about seeds here: brainly.com/question/18799172
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If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula
![A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)](https://tex.z-dn.net/?f=A_x%20%3D%20%7CA%7Ccos%28%5Calpha%29%5C%5C%5C%5CA_y%20%3D%20%7CA%7Csin%28%5Calpha%29)
Where | A | is the magnitude of the vector and
is the angle that it forms with the x axis in the opposite direction to the hands of the clock.
In this problem we know the value of Ax and Ay and we need the angle
.
Vector A is in the 4th quadrant
So:
![A_x = 6\\\\A_y = -6.5](https://tex.z-dn.net/?f=A_x%20%3D%206%5C%5C%5C%5CA_y%20%3D%20-6.5)
So:
![|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846](https://tex.z-dn.net/?f=%7CA%7C%20%3D%20%5Csqrt%7B6%5E2%20%2B%20%28-6.5%29%5E2%7D%5C%5C%5C%5C%7CA%7C%20%3D%208.846)
So:
![Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)](https://tex.z-dn.net/?f=Ay%20%3D%20-6.5%20%3D%208.846cos%28%5Calpha%29%5C%5C%5C%5Csin%28%5Calpha%29%20%3D%20%5Cfrac%7B-6.5%7D%7B8.846%7D%5C%5C%5C%5Csin%28%5Calpha%29%20%3D%20-0.7348%5C%5C%5C%5C%5Calpha%20%3D%20sin%5E%7B-%201%7D%28-%200.7348%29)
= -47.28 ° +360° = 313 °
= 313 °
Option 4.
Answer:
just search up a ven-diagram and then try to draw it or trace it then use it for ur question
Explanation:
You are correct the answer would be C
hope i helps