Answer:
The answer to your question is 41.6 g of AgCl
Explanation:
Data
mass of NH₄Cl = 15.5 g
mass of AgNO₃ = excess
mass of AgCl = 35.5 g
theoretical yield = ?
Process
1.- Write the balanced chemical reaction.
NH₄Cl + AgNO₃ ⇒ AgCl + NH₄NO₃
2.- Calculate the molar mass of NH₄Cl and AgCl
NH₄Cl = 14 + 4 + 35.5 = 53.5 g
AgCl = 108 + 35.5 = 143.5 g
3.- Calculate the theoretical yield
53.5 g of NH₄Cl -------------------- 143.5 g of AgCl
15.5 g of NH₄Cl ------------------- x
x = (15.5 x 143.5) / 53.5
x = 2224.25 / 53.5
x = 41.6 g of AgCl
Answer:
C Metals are ductile, meaning they can be pulled into wires.
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Answer:
M₁ = 0.178 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid,
M₂ = concentration of base ,
V₂ = volume of base,
from , the question ,
M₁ = ?
V₁ = 20.0 mL
M₂ = 0.158 M
V₂ = 22.60 mL
Using the above formula , the molarity of the acid , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 20.0 mL = 0.158 M * 22.60 mL
M₁ = 0.178 M
They are all biotic factors, meaning they were once alive or were alive. (an abiotic factor is something that has never lived.) hope this helped.
