PE = mgh
where
m = mass
g = acceleration due to gravity
h = height
fault-block mountains. hope this helps
The microwave ovens rotate at a rate of about 0.105 rev/s.
The microwave rotation is the number of revolutions in a unit of time. To change the unit for angular velocity, assume that the quantity is multiplied by the unit it has. Then change to the desired units. The angular velocity is denoted by ω and has a magnitude of 6.3 rev/min.
ω = 6.3 rev/min
![\omega = 6.3 \times \frac{1 \: rev}{1 \: min}](https://tex.z-dn.net/?f=%5Comega%20%3D%206.3%20%5Ctimes%20%5Cfrac%7B1%20%5C%3A%20rev%7D%7B1%20%5C%3A%20min%7D)
- 1 minute = 60 seconds
- The revolution unit didn't change
![\omega = 6.3 \times \frac{1 \: rev}{60 \: seconds}](https://tex.z-dn.net/?f=%5Comega%20%3D%206.3%20%5Ctimes%20%5Cfrac%7B1%20%5C%3A%20rev%7D%7B60%20%5C%3A%20seconds%7D)
![\omega = \frac{6.3 \: rev}{60 \: seconds}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cfrac%7B6.3%20%5C%3A%20rev%7D%7B60%20%5C%3A%20seconds%7D)
ω = 0.105 rev/s
Learn more about Angular velocity here: brainly.com/question/29344944
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To develop this problem we will apply the considerations made through the concept of Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. At first the source is moving towards the observer. Than the perceived frequency at first
![F_1 = F \frac{{343}}{(343-V)}](https://tex.z-dn.net/?f=F_1%20%3D%20F%20%5Cfrac%7B%7B343%7D%7D%7B%28343-V%29%7D)
Where F is the actual frequency and v is the velocity of the ambulance
Now the source is moving away from the observer.
![F_2 = F\frac{343}{(343+V)}](https://tex.z-dn.net/?f=F_2%20%3D%20F%5Cfrac%7B343%7D%7B%28343%2BV%29%7D)
We are also so told the perceived frequency decreases by 11.9%
![F_2 = F_1 - 9.27\% \text{ of } F_1](https://tex.z-dn.net/?f=F_2%20%3D%20F_1%20-%209.27%5C%25%20%5Ctext%7B%20of%20%7D%20F_1)
![F_2 = F_1-0.0927F_1](https://tex.z-dn.net/?f=F_2%20%3D%20F_1-0.0927F_1)
![F_2 = 0.9073F_1](https://tex.z-dn.net/?f=F_2%20%3D%200.9073F_1)
Equating,
![F\frac{343}{(343+V)}= 0.9073(F\frac{343}{(343-V)})](https://tex.z-dn.net/?f=F%5Cfrac%7B343%7D%7B%28343%2BV%29%7D%3D%200.9073%28F%5Cfrac%7B343%7D%7B%28343-V%29%7D%29)
![\frac{1}{(343+V)}= 0.9073\frac{1}{(343-V)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%28343%2BV%29%7D%3D%200.9073%5Cfrac%7B1%7D%7B%28343-V%29%7D)
![0.9073(343+V) = 343-V](https://tex.z-dn.net/?f=0.9073%28343%2BV%29%20%3D%20343-V)
![(0.9073)(343)+(0.9073)V = 343-V](https://tex.z-dn.net/?f=%280.9073%29%28343%29%2B%280.9073%29V%20%3D%20343-V)
![V+0.9073V = 343-(0.9073)(343)](https://tex.z-dn.net/?f=V%2B0.9073V%20%3D%20343-%280.9073%29%28343%29)
Solving for V,
![V = 16.67 m/s](https://tex.z-dn.net/?f=V%20%3D%2016.67%20m%2Fs)
Answer: B. argon, neon, xeno
Explanation:
All these elements listed here are part of the group 18 of the periodic table, which is the last group on the right. All these elements are also called 'noble gases'. Their main property is that they have their last energy shell completely filled with electrons: so they do not easily give/receive electrons to make bonds with other elements. For this reason, these elements have the most stable electron configuration, and they do not react with other elements.