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Nadusha1986 [10]
3 years ago
5

In the mirror diagram shown, Which is the normal?

Chemistry
2 answers:
o-na [289]3 years ago
7 0

Answer:

C

Explanation:

always look for the line that is perpendicular to the surface

Anon25 [30]3 years ago
7 0

Answer:

It's <u><em>C   Chief</em></u>

Explanation:

I got it right.

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What is common to all elements in the same group on the periodic table
marin [14]
They all have the same number of electrons.
3 0
3 years ago
Read 2 more answers
HELP PLS THANK YA!!!
eduard

Answer:

there is the answers. hope this helps

5 0
3 years ago
Help please?!??!??!?!?!
GalinKa [24]

Answer:

A

Explanation:

Matter is anything that has weight and occupies space. Weight is synonymous to mass

3 0
3 years ago
Any help with these questions would help i'm lost
SSSSS [86.1K]

Answer:

1.  31.25 mL

2.  1.98 g/L

3.  0.45 g/mL

Explanation:

For each of the problems, you need to perform unit conversions.  You need to use the information given to you to convert to a specific unit.

1.  You need volume (mL).  You have density (g/mL) and mass (g).  Divide mass by density.  You will cancel out mL and be left with g.

(50.0 g)/(1.60 g/mL) = 31.25 mL

2.  You are given grams and liters.  You need to find density with units g/L.  This means that you have to divide grams by liters.

(0.891 g)/(0.450 L) = 1.98 g/L

3.  You have to find density again but this time with units g/mL.  Divide the given mass by the volume.

(10.0 g)/(22.0 mL) = 0.45 g/mL

5 0
3 years ago
What is the molarity of a NaCl stock used to make 750 ml of a dilute 10 mM solution if 5 ml of the concentrated solution was use
ch4aika [34]

Explanation:

The given data is as follows.

          M_{1} = 10 mM = 10 \times 10^{-3} M

          V_{1} = 750 ml,           V_{2} = 5 ml

          M_{2} = ?

Therefore, calculate the molarity of given NaCl stock as follows.

                  M_{1} \times V_{1} = M_{2} \times V_{2}

                  10 \times 10^{-3} \times 750 ml = M_{2} \times 5 ml

                   M_{2} = 1.5 M

Thus, we can conclude that molarity of given NaCl stock is 1.5 M.        

7 0
3 years ago
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