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WINSTONCH [101]
3 years ago
8

Why is it incorrect to call an astronaut massless?

Chemistry
2 answers:
Reil [10]3 years ago
7 0
<span>Why is it incorrect to call an astronaut massless?

its incorrect because everything has mass wheather in space or on a planet.</span>
Fofino [41]3 years ago
5 0
Because mass is the amount of thing is in someone it would be correct to call an astronaut weightless if they were in space

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John dissolves .5g of a white powder in 25g of benzene (FP 5oC) (kf benzene is 5.1) and finds the solution freezes at 3.7oC. Det
navik [9.2K]

Answer:

The compound has a molar mass of 78.4 g/mol

Explanation:

Step 1: data given

Mass of a sample = 0.5 grams

Mass of benzene = 25 grams

Freezing poing = 5 °C

Kf of benzene = 5.1 °C/m

Freezing point solution = 3.7 °C

Step 2: Calculate molality

ΔT = i*Kf*m

⇒with ΔT = the freezing point depression = 5.0 - 3.7 = 1.3 °C

⇒with i = the can't hoff factor = 1

⇒with Kf = the freezing point depression constant of benzene = 5.1 °C/m

⇒with m = the molality

1.3 = 5.1 * m

m = 1.3 / 5.1

m = 0.255 moles /kg

Step 3: Calculate moles

Molality = moles / mass benzene

0.255 molal = moles / 0.025 kg

Moles = 0.255 molal * 0.025 kg

Moles = 0.006375 moles

Step 4: Calculate molar mass of the compound

Molar mass compund = mass / moles

Molar mass compound = 0.5 grams / 0.006375 moles

Molar mass compound = 78.4 g/mol

The compound has a molar mass of 78.4 g/mol

7 0
3 years ago
Al comenzar la reacción: N2(g) + 2O2(g) ------&gt; 2NO2(g) existe 1 mol de N2 y 2 moles de O2 y al
miss Akunina [59]

Answer:

65

Explanation:

estion

Al comenzar la reacción: N2(g) + 2O2(g) ------> 2NO2(g) existe 1 mol de N2 y 2 moles de O2 y al

finalizarla está presente una mezcla formada por 2,2 moles en total, ¿cuál es el rendimiento para la

reacción?

7 0
2 years ago
Automotive airbags inflate when a sample of sodium azide, NaN3, is very rapidly decomposed.
Kobotan [32]

Answer:

148 g

Explanation:

Step 1: Write the balanced equation for the decomposition of sodium azide

2 NaN₃ ⇒ 2 Na + 3 N₂

Step 2: Calculate the moles corresponding to 95.8 g of N₂

The molar mass of N₂ is 28.01 g/mol.

95.8 g × 1 mol/28.01 g = 3.42 mol

Step 3: Calculate the moles of NaN₃ needed to form 3.42 moles of N₂

The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.42 mol = 2.28 mol.

Step 4: Calculate the mass corresponding to 2.28 moles of NaN₃

The molar mass of NaN₃ is 65.01 g/mol.

2.28 mol × 65.01 g/mol = 148 g

8 0
2 years ago
I just don’t know what to do
ValentinkaMS [17]

Answer:

I dont know if this is correct.. but maybe in the tool row, put graduated cylinder because you use graduated cylinders to measure water and for units put milliliters or liters?? Sorry if this isnt correct i wouldnt know what else to put !

Explanation:

3 0
3 years ago
Explain the concept: Law of Multiple Proportions.<br> Short and simple please
cricket20 [7]
In chemistry the law of multiple proportions states that if two elements from more than one compound between them then the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers .
4 0
3 years ago
Read 2 more answers
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