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katovenus [111]
3 years ago
10

Mudcracks result from:

Chemistry
2 answers:
Ksenya-84 [330]3 years ago
6 0

Drying of the lake beds

Sonbull [250]3 years ago
4 0
Drying of lake beds :)
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The image compares the arrangement of electrons in two different neutral atoms.
jekas [21]

Answer:

  • <u>Option b. Atom P has an estimated Zeff of 7 and is therefore to the right of Atom Q, which has a Zeff of 6.</u>

Explanation:

Please, find attached the figures of both atom Q and atom P corresponding to this question.

The <u>features of atom Q are</u>:

  • Each <em>black sphere</em> represents an electron
  • In total this atom has 8 electrons: 2 in the inner shell and 6 in the outermost shell.
  • Since it is assumed that the atom is neutral, it has 8 protons: one positive charge of a proton balances one negative charge of an electron. Thus, the atomic number of this atom is 8.
  • Since only two shells are ocuppied, you can assert that the atom belongs to the period 2 (which is confirmed looking into a periodic table with the atomic number 8).
  • <em>Zeff </em>is the effective nuclear charge of the atom. It accounts for the  net positive charge the valence electrons experience. And may, in a very roughly way, be estimated as the number of protons less the number of electrons in the inner shells. Thus, for this atom, an estimated  Z eff = 8 - 2 = 6.

The <u>features of atom P</u> are:

  • Again, each black sphere represents an electron
  • In total this atom has 9 electrons: 2 in the inner shell and 7 in the outermost shell.
  • Since it is assumed that the atom is neutral, it has 9 protons.
  • The atomic number of this atom is 9.
  • Using the same reasoning used for atom Q, this atom is also in the period 2.
  • Estimated Z eff = 9 - 2 = 7.

Then, since atom P has a greater Z eff than atom Q (an estimated Zeff of 7 for atom P against an estimated Z eff of 6 for atom Q),  and both atoms are in the same period, you can affirm that <em>atom P</em> has a greater atomic number and<em> is therefore to the right of atom Q</em>.

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3 years ago
State the type of bonding—ionic, covalent, or metallic—you would expect in each: (c) Na(s).
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Na(s) forms an ionic bond.

<h3>What is ionic bond?</h3>

The main interaction in ionic compounds is ionic bonding, a type of chemical bonding that involves the electrostatic attraction between two atoms or ions with dramatically differing electronegativities. Along with metallic and covalent bonds, it is one of the most common types of bonds. Atoms (or collections of atoms) possessing an electrical charge are known as ions. Ions with negative charges are created when atoms gain electrons (called anions). Positively charged ions are produced when atoms lose electrons (called cations). In contrast to covalence, this electron transfer is referred to as electrovalence.

Ionic chemicals normally do not conduct electricity when solid, only when molten or in solution. Depending on the charge of the ions they are made of, ionic compounds typically have a high melting point.

To learn more about ionic bond from the given link:

brainly.com/question/13526463

#SPJ4

5 0
1 year ago
Are these gases lighter than or denser than air? How can you tell?
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Calcium forms ions with a charge of +2. Iodine forms ions with a charge of -1. Which of the following would represent an ionic c
astra-53 [7]

 The   formula that would represent an ionic  compound  that is composed of calcium and iodide ions  is   CaI2

 Explanation

Ionic compound  CaI₂ is formed  when Calcium form cation ( <em>a positively charged ion</em>) by losing 2 electrons while two iodine atoms form  anion ( <em>a negatively charged ion</em>)  by  gaining one electron each.

When writing down   formula of ionic compound, the formula  of cation  is written  first followed by anion  formula. therefore  Ca is written  first  followed by I.

The numeric subscript 2 after I(iodine) indicate that 2 atoms of iodine are involved  in bonding.

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