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Alenkinab [10]
3 years ago
12

IF an Axonal Membrane transiently becomes very permeable to Na+ ions then the membrane potential of the cell wall will approach:

a. (+)132 mVb. (+)50 mVc. (-)60 mVd. (+)70 mVe. (-)94 mV
Chemistry
1 answer:
posledela3 years ago
7 0

Answer:

The correct option is D ((+)70 mV)

Explanation:

IF an Axonal Membrane transiently becomes very permeable to Na+ ions then the membrane potential of the cell wall will approach (+)70 mV.

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2 grams of a substance was dissolved in 75.0 g of water resulting in a temperature decrease from 23.1 ⁰C to 18.7 ⁰C. The specifi
RUDIKE [14]
<h3>Answer:</h3>

1379.4 Joules

<h3>Explanation:</h3>
  • The quantity of heat is calculated multiplying the mass of a substance by heat capacity and the change in temperature.

Therefore;

Quantity of heat = Mass × specific heat capacity × Change in temperature

Q = mcΔT

In this case;

The substance dissolved in water gained heat while water lost heat energy.

Thus, Heat gained by the substance = heat lost by water

Heat associated with the water  

Mass of water = 75 g

Change in temperature = 4.4°C

Specific heat capacity =  4.18 J/g·⁰C

Heat = mcΔT

        = 75 g × 4.18 J/g·⁰C × 4.4 °C

        =1379.4 Joules

5 0
3 years ago
A titration of 25.0 mL of a solution of the weak base aniline, C6H5NH2, requires 25.67 mL of 0.175 M HCl to reach the equivalenc
Lorico [155]

Answer:

a. 0.180M of C₆H₅NH₂

b. 0.0887M C₆H₅NH₃⁺

c. pH = 2.83

Explanation:

a. Based in the chemical equation:

C₆H₅NH₂(aq) + HCl(aq) → C₆H₅NH₃⁺(aq) + Cl⁻(aq)

<em>1 mole of aniline reacts per mole of HCl</em>

Moles required to reach equivalence point are:

Moles HCl = 0.02567L ₓ (0.175mol / L) = 4.492x10⁻³ moles HCl = moles C₆H₅NH₂

As the original solution had a volume of 25.0mL = 0.0250L:

4.492x10⁻³ moles C₆H₅NH₂ / 0.0250L = 0.180M of C₆H₅NH₂

b. At equivalence point, moles of C₆H₅NH₃⁺ are equal to initial moles of C₆H₅NH₂, that is 4.492x10⁻³ moles

But now, volume is 25.0mL + 25.67mL = 50.67mL = 0.05067L. Thus, molar concentration of C₆H₅NH₃⁺ is:

[C₆H₅NH₃⁺] = 4.492x10⁻³ moles / 0.05067L = 0.0887M C₆H₅NH₃⁺

c. At equivalence point you have just 0.0887M C₆H₅NH₃⁺ in solution. C₆H₅NH₃⁺ has as equilibrium in water:

C₆H₅NH₃⁺(aq) + H₂O(l) → C₆H₅NH₂ + H₃O⁺

Where Ka = Kw / Kb = 1x10⁻¹⁴ / 4.0x10⁻¹⁰ =

<em>2.5x10⁻⁵ = [C₆H₅NH₂] [H₃O⁺] / [C₆H₅NH₃⁺]</em>

When the system reaches equilibrium, molar concentrations are:

[C₆H₅NH₃⁺] = 0.0887M - X

[C₆H₅NH₂] = X

[H₃O⁺] = X

Replacing in Ka formula:

2.5x10⁻⁵ = [X] [X] / [0.0887M - X]

2.2175x10⁻⁶ - 2.5x10⁻⁵X = X²

0 = X² + 2.5x10⁻⁵X - 2.2175x10⁻⁶

Solving for X:

X = -0.0015 → False solution. There is no negative concentrations.

X = 0.001477 → Right solution.

As [H₃O⁺] = X, [H₃O⁺] = 0.001477

Knowing pH = -log [H₃O⁺]

pH = -log 0.001477

<h3>pH = 2.83</h3>

7 0
3 years ago
What is the central conflict in "Ellen foster"?
photoshop1234 [79]

major conflict. Ellen continually suffers abuse by her neglectful caretakers and searches for a stable home and loving family. rising action. Ellen is placed in a number of temporary homes, all of which are unhappy, and she longs for a home where she is loved and cared for.


7 0
3 years ago
All vertbrate have an
Pepsi [2]
They all have endoskeletons that are formed of bone or cartilage. Hope this helped! (:
7 0
3 years ago
Read 2 more answers
How many moles of lead, Pb, are in 1.50 x 10^12 atoms of lead?
gulaghasi [49]
<h3>Answer:</h3>

2.49 × 10⁻¹² moles Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.50 × 10¹² atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                                         \displaystyle 1.50 \cdot 10^{12} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})
  2. Multiply:                                                                                                           \displaystyle 2.49087 \cdot 10^{-12} \ moles \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2.49087 × 10⁻¹² moles Pb ≈ 2.49 × 10⁻¹² moles Pb

5 0
3 years ago
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