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Vsevolod [243]
3 years ago
9

A long rod of 60-mm diameter and thermophysical properties rho= 8000 kg/m3, c= 500 J/kg·K, and k= 50 W/m·K is initially at a uni

form temperature and is heated in a forced convection furnace maintained at 750 K. The convection coefficient is estimated to be 1000 W/m2· K. What is the centerline temperature of the rod when the surface temperature is 550 K?
Engineering
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

Tc =    = 424.85 K

Explanation:

Data given:

D = 60 mm = 0.06 m

\rho = 8000 kg/m^3

k = 50 w/m . k

c = 500 j/kg.k

h_{\infty} = 1000 w/m^2

t_{\infity} = 750 k

t_w = 500 K

surface area = As = \pi dL

\frac{As}{L} = \pi D = \pi \timeS 0.06

HEAT FLOW Q  is

Q = h_{\infty} As (T_[\infty} - Tw)

 = 1000 \pi\times 0.06 (750-500)

  = 47123.88 w per unit length of rod

volumetric heat rate

q = \frac{Q}{LAs}

  = \frac{47123.88}{\frac{\pi}{4} D^2 \times 1}

q = 1.66\times 10^{7} w/m^3

Tc = \frac{- qR^2}{4K} + Tw

= \frac{ - 1.67\times 10^7 \times (\frac{0.06}{2})^2}{4\times 56} +  500

   = 424.85 K

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<u>Explanation:</u>

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3 years ago
For a very rough pipe wall the friction factor is constant at high Reynolds numbers. For a length L1 the pressure drop over the
Goshia [24]

Answer:

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Explanation:

The pressure drop is directly proportional to the length of the pipe. Then, the new pressure drop is two time the previous one.

\Delta p_{2} = 2\cdot \Delta p_{1}

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3 years ago
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3 0
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2. A F-22 Raptor has just climbed through an altitude of 9,874 m at 1,567 kph when a disk
BabaBlast [244]

The pressure difference across the sensor housing will be "95 kPa".

According to the question, the values are:

Altitude,

  • 9874

Speed,

  • 1567 kph

Pressure,

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The temperature will be:

→ T = 15.04-[0.00649(9874)]

→     = 15.04-64.082

→     = -49.042^{\circ} C

now,

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hence,

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Thus the above solution is correct.

Learn more about pressure difference here:

brainly.com/question/15732832

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