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3 years ago

Predict the product of this chemical equation. please explain how u did it. Do not balance after finding answer.

Chemistry

1 answer:

Oksanka [162]3 years ago

8 0

Answer:

The products are CO₂ and H₂O.

The ballanced equation is this:

2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O

Explanation:

In any chemical reaction, where you see that you have a compound reacting only with oxygen (O₂), you are in front of combustion.

Products in combustion are always water vapor and carbon dioxide.

Take a look to the methane combustion.

CH₄ + 2O₂ → CO₂ + 2H₂O

1 mol of methane reacts with 2 moles of oxygen to form 1 mol of CO₂ and 2 moles of water.

This is the combustion for an alkene where 2 moles of the alkene reacts with 11 moles of oxygen to make water and CO₂ like this:

2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O

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What is the mass of 11.8 moles of water?

uysha [10]

First, find how many grams are in 1 mole of water.

For a hydrogen atom, there is about 1 gram per mole. For an oxygen atom, there are about 16 grams per mole.

In H2O, there are two hydrogen atoms and one oxygen atom. This means there are 18 grams in one mole of water. Multiply the mass in one mole by your number of moles.

18 x 11.8 = 212.4 grams

You have 212.4 grams of water.

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3 years ago

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3 years ago

The mechanisms of most common reactions consist of two or more elementary steps, each of which describes a single molecular even

olga2289 [7]

Answer:

The correct answer is "True".

Explanation:

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3 years ago

Calculate the enthalpy of the reaction

harkovskaia [24]

Answer : The enthalpy of the reaction is, -2552 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given enthalpy of reaction is,

$4B(s)+3O_2(g)\rightarrow 2B_2O_3(s)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $B_2O_3(s)+3H_2O(g)\rightarrow 3O_2(g)+B_2H_6(g)$ $\Delta H_A=+2035kJ$

(2) $2B(s)+3H_2(g)\rightarrow B_2H_6(g)$ $\Delta H_B=+36kJ$

(3) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)$ $\Delta H_C=-285kJ$

(4) $H_2O(l)\rightarrow H_2O(g)$ $\Delta H_D=+44kJ$

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :

(when we are reversing the reaction then the sign of the enthalpy change will be change.)

The expression for enthalpy of the reaction will be,

$\Delta H=-2\times \Delta H_A+2\times \Delta H_B-6\times \Delta H_C-6\times \Delta H_D$

$\Delta H=-2(+2035kJ)+2(+36kJ)-6(-285kJ)-6(+44)$

$\Delta H=-2552kJ$

Therefore, the enthalpy of the reaction is, -2552 kJ/mole

4 0

3 years ago

I neeeedddd hhheeelppppppllsssss

padilas [110]

Answer:

I believe that it is the 2nd option.

Explanation:

My reasonings are because C4H10O has 7 isomers. In which 4 are alcohol and the other 3 are ether.

The first option is ethers, specifically ethoxyethane.

The third option is ethers, specifically 1-methoxypropane.

The fourth option is an alcohol, specifically 1- butanol.

Therefore, leads us to the 2nd option that it is NOT an isomer of C4H10O

8 0

2 years ago