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irina1246 [14]
3 years ago
13

A 0.001kg bullet is fired with a velocity of 800m/s into a soft wood of mass 1kg resting on a smooth surface. Find the final vel

ocity if the bullet is fully embedded I n the wood after the collision​
Physics
1 answer:
V125BC [204]3 years ago
4 0

The final velocity of the bullet+block is 0.799 m/s

Explanation:

We can solve this problem by applying the principle of conservation of momentum: in fact, the total momentum of the bullet-block system must be conserved before and after the collision.

Mathematically, we can write:

mu+MU=(m+M)v

where

m = 0.001 kg is the mass of the bullet

u = 800 m/s is the initial velocity of the bullet

M = 1 kg is the mass of the block

U = 0 is the initial velocity of the block (initially at rest)

v is the final combined velocity of the bullet and the block

Solving the equation for v, we  find the final velocity:

v=\frac{mu}{m+M}=\frac{(0.001)(800)}{0.001+1}=0.799 m/s

Learn more about conservation of momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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          n = √ (8  9.1 10⁻³¹ (1.4 10⁻⁹)²  30.4 10⁻¹⁹ / (6.63 10⁻³⁴)²

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b) We substitute for the calculation of energy

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      E₁₀ = 3.08 10⁻¹⁸ j (1ev / 1.6 10⁻¹⁹J)

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the result with significant figures is

        E₁₀ = 19.25 eV

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