Question

An electric field of intensity 4.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true.

Answer 1

Answer:

Electric flux will be equal to $1041.25Nm^2/C$

Explanation:

We have given electric field $E=4.25KN/C=4.25\times 10^3N/C=4250N/C$

Sides of rectangle is given as 0.350 m wide and 0.700 m long

So length of rectangle l = 0.7 m and width w = 0.35 m

So area of rectangle $A=0.7\times 0.35=0.245m^2$

It is given that electric field is along the x axis

So angle between plane and electric filed $\Theta =0^{\circ}$

So electric flux will be equal to $\Phi =EAcos\Theta =4250\times 0.245\times cos0^{\circ}=1041.25Nm^2/C$