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elena-14-01-66 [18.8K]
4 years ago
13

A pen cap floats in a plastic lemonade 3/4 full of water vif you squeeze the bottle the pen cap sinks to the bottom if you then

let go of the bottle the pen cap floats to the surfce whe the bottle squeezed what ,if anything happens to the distance between the air molecules inside the bottle????????/
Physics
1 answer:
elena-s [515]4 years ago
4 0

Answer:

The pressure of the air molecules inside the pen cap increases and the volume occupied by the air decreases such that the combined volume occupied by the pen cap and the air volume reduces while the combined mass of the pen cap and the air molecules remain the same

Given that density = The mass/Volume, we have that the density varies inversely as the volume, and as the volume reduces, the density increases

Upon squeezing, therefore, as the new combined density of the pen cap and the air molecules rises to more than the density of the water in the bottle, then, the pen cap air molecule is relatively more denser than the water, which will result in the pen cap sinking to the bottom of the bottle

Explanation:

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andrey2020 [161]

Answer:

9.8 m/s2

Explanation:

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miskamm [114]
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<u>The simple method:
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3 years ago
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The solution for this problem is:

 
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7 0
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A spring with a spring constant of 50 N/m is stretched 15cm. What is the force and energy associated with this stretching?
Olenka [21]
Data:
F (force) = ? (Newton)
k (<span>Constant spring force) = 50 N/m
x (</span>Spring deformation) = 15 cm → 0.15 m

Formula:
F = k*x

Solving: 
F = k*x
F = 50*0.15
\boxed{\boxed{F = 7.5\:N}}\end{array}}\qquad\quad\checkmark

Data:
E (energy) = ? (joule)
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Formula:
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E = \frac{k*x^2}{2}
E =  \frac{50*0.15^2}{2}
E =  \frac{50*0.0225}{2}
E =  \frac{1.125}{2}
\boxed{\boxed{E = 0.5625\:J}}\end{array}}\qquad\quad\checkmark

7 0
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