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3 years ago

When a star is moving away the light waves appear to be....

Physics

1 answer:

BabaBlast [244]3 years ago

4 0

When a star is moving away from earth it appears blue

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A source charge of 5. 0 µC generates an electric field of 3. 93 × 105 at the location of a test charge. How far is the test char

lora16 [44]

Answer:

r = 0.338 meters

Explanation:

Q = Source charge

q = Test charge

5μC= 5*10^-6 C

Start with the electric field equation:

$E = \frac{F}{q}$

and Coulombs law

$F=\frac{k|Qq|}{r^2}$

Combining these functions we get:

$E=\frac{k|Q|}{r^2}$

As you can see the test charge cancels so we do not need the value of it.

Plug in your numbers:

$3.93*10^5=\frac{(8.99*10^9)(5*10^-^6)}{r^2}$

solve for r

$r=\sqrt{\frac{(8.99*10^9)(5*10^-^6)}{(3.93*10^5)} }$

$r= 0.338 meters$

6 0

2 years ago

A car accelerates from rest (v. 0 m/s) with a constant acceleration of

oksano4ka [1.4K]

Heya!!

For calculate final velocity, lets applicate formula

$\boxed{V=V_o+a*t}$

<u>Δ Being Δ</u>

V = Final Velocity = ?

Vo = Initial velocity = 0 m/s

a = Aceleration = 5 m/s²

t = Time = 12 s

⇒ Let's replace according the formula:

$\boxed{V=0\ m/s +5\ m/s*12\ s}$

⇒ Resolving

$\boxed{V=60\ m/s}$

Result:

The velocity after 10 sec is <u>60 meters per second (m/s)</u>

Good Luck!!

4 0

3 years ago

An electron moves north at a velocity of 4.5 × 104 m/s and has a magnetic force of 7.2 × 10-18 n exerted on it. if the magnetic

Mice21 [21]

The magnetic force on a moving charge is given by:

$F=qvB \sin \theta$

where q is the charge, v is the speed of the charge, B is the magnetic field intensity and $\theta$ is the angle between the directions of B and v.

In our problem, the charge is an electron ( $q=1.6 \cdot 10^{-19}C$ ), the velocity of the charge is $v=4.5 \cdot 10^4 m/s$ , the magnetic force is $F=7.2 \cdot 10^{-18} N$ and the angle between the direction of v and B is $\theta=90^{\circ}$ , so $\sin \theta=1$ and we can ignore the sine in the formula. Therefore, if we rearrange the equation and we put these numbers in, we can find the intensity of the magnetic field: