Answer:
18 000 m/ s
Explanation:
speed = wavelength * frequency
speed = 1.2 * 15 000 = 18 000 m/s
The minimum coefficient of friction to avoid slippage of the coin is 0.23.
<h3>
Minimum coefficient of friction</h3>
The minimum coefficient of friction can determined from the maximum speed of the coin.
ma = μmg
mv²/r = μmg
v²/r = μg
v² = μgr
μ = v²/(gr)
μ = (ωr)²/(gr)
μ = ω²r/g
μ = (7.95² x 0.035)/(9.8)
μ = 0.23
Learn more about coefficient of friction here: brainly.com/question/20241845
#SPJ11
Answer:
option b. <em>uniform</em><em> </em><em>population</em>
Answer:
121Sb=57.2%
123Sb=42.8%
Explanation:
We are given that
Atomic mass of 121Sb=120.904 amu
Atomic mass of 123Sb=122.904 amu
Average atomic mass of antimony=121.760 amu
We have to find the percent of each of the isotope.
Let x be the percent of 121Sb and 1-x be the percent of 123Sb.
Using formula of average atomic weight
Average atomic weight=atomic weight of 121Sb
percentage abundance of isotope 121Sb+atomic weight of 123Sb
percentage abundance of isotope 123Sb
Substitute the values






Percentage of 121Sb=
57.2%
Abundance of isotope 123Sb=1-0.572=0.428
Percentage of isotope 123Sb=
42.8%