A rechargeable battery is capable of delivering a current of 0.25 A for 1800 s at a potential difference of 1.5 V.

Physics

1 answer:

avanturin [10]2 years ago

5 0

Answer:

a. q=450 c

b. E=675 J

Explanation:

Direct Current (DC)

It's the flow of electric charges in one direction driven by a constant voltage circuit. The intensity of the current flow is computed as

$\displaystyle I=\frac{q}{t}$

Where q is the constant flow of charge in time t

The energy of an element providing Voltage V, current I during a time t is

$E=V.I.t$

a. The charge can be computed by solving the first equation for q

$q=I.t=0.25\ A.\ 1800\ s=450\ c$

b. The energy transferred by the battery is

$E=(1.5).(0.25).(1800)=675\ J$

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