All categories

2 years ago

Energy ___________.

Physics

2 answers:

Setler79 [48]2 years ago

8 0

It’s the first one it’s used to do work

AVprozaik [17]2 years ago

7 0

Answer:

BRAINLIEST PLSSSSSSSSSSSSSSSSSSSSSSSS

Thermodynamics

Explanation:

Thermodynamics is the study of energy. First Law of Thermodynamics: Energy can be changed from one form to another, but it cannot be created or destroyed. The total amount of energy and matter in the Universe remains constant, merely changing from one form to another.

You might be interested in

lys-0071 [83]

Answer:

The object will have an upward acceleration

Explanation:

Let's consider the forces applied on the box. We have only two forces:

- The applied force of push, $F_p$ , downward

- The force of gravity, $W$ , (also known as weight of the object), downward

Therefore, the net force on the box is:

$F_{net}=F_p -W$

Here, we know that force applied is equal or greater than the weight, so

$F_p \geq W$

And therefore the net force is greater than zero:

$F_{net}\geq 0$ (1)

According to Newton's second law of motion, the net force on the box is equal to the product between its mass and its acceleration:

$F_{net}=ma$

where

m is the mass of the box

a is its acceleration

Given (1), this means that

$a\geq 0$

Therefore, the box will have an upward acceleration.

In this case force example we have:

$F_p = 100 N\\W = 40 N$

So the mass of the box is

$m=\frac{W}{g}=\frac{40}{10}=4 kg$

So the net force is

$F_{net}=F_p-W=100-40=60 N$

And the acceleration is

$a=\frac{F_{net}}{m}=\frac{60}{4}=15 m/s^2$

4 0

3 years ago

Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (

alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b) $E_1=\dfrac{\sigma}{\epsilon_0}$

c) $E_2=\dfrac{\sigma}{\epsilon_0}$

Explanation:

Let $\sigma$ be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field so the Electric Flux due to it is zero.