Answer:
velocity = 472 m/s
velocity = 52.4 m/s
Explanation:
given data
steady rate = 0.750 m³/s
diameter = 4.50 cm
solution
we use here flow rate formula that is
flow rate = Area × velocity .............1
0.750 =
× (4.50×
)² × velocity
solve it we get
velocity = 472 m/s
and
when it 3 time diameter
put valuer in equation 1
0.750 =
× 3 × (4.50×
)² × velocity
velocity = 52.4 m/s
The energy stored in a capacitor is given by:
![U= \frac{1}{2}CV^2](https://tex.z-dn.net/?f=U%3D%20%5Cfrac%7B1%7D%7B2%7DCV%5E2%20)
where
U is the energy
C is the capacitance
V is the potential difference
The capacitor in this problem has capacitance
![C=3.0 \mu F = 3.0 \cdot 10^{-6} F](https://tex.z-dn.net/?f=C%3D3.0%20%5Cmu%20F%20%3D%203.0%20%5Ccdot%2010%5E%7B-6%7D%20F)
So if we re-arrange the previous equation, we can calculate the potential V that should be applied to the capacitor to store U=1.0 J of energy on it:
With a 30 mph head wind it takes the plane 18.52 hours to fly 5000 miles. ANSWER 2: With a 30 mph tail wind it takes the plane 15.15 hours to fly 5000 miles.
On Earth, 1 g = 9.8 m/s² .
5 g = 5 · (9.8 m/s²)
5 g = 49 m/s²
Answer:
27.22 m/s
Explanation:
Let the speed of clay before impact is u.
the speed of clay and target is v after impact.
use conservation of momentum
momentum before impact momentum after impact
mass of clay x u = (mass of clay + mass of target) x v
100 x u = (100 + 500) x v
u = 6 v .....(1)
distance, s = 2.1 m
μ = 0.5
final velocity is zero. use third equation of motion
v'² = v² + 2as
0 = v² - 2 x μ x g x s
v² = 2 x 0.5 x 9.8 x 2.1 = 20.58
v = 4.54 m/s
so by equation (1)
u = 6 x 4.54 = 27.22 m/s
thus, the speed of clay before impact is 27.22 m/s.