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amid [387]
3 years ago
11

Which statement is correct?

Chemistry
2 answers:
Shtirlitz [24]3 years ago
5 0

Answer:

The volumes of 1 mol of CO2 and 1 mol of N2, gases are the same.

Explanation:

1 mole of a gas occupy 22.4L at stp. This is true for all gases. So,

1mol of CO2 = 22.4L

1mole of N2 = 22.4L

From the above illustration, 1mole of CO2 and 1mole N2 have the same volume at stp

Natasha2012 [34]3 years ago
4 0

Answer: The volumes of 1 mol of CO2 and 1 mol of N, gases are the same.

Explanation:

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A 0.2436-g sample of an unknown substance was dissolved in 20.0 ml of cyclohexane. The density of cyclohexane is 0.779 g/ml. The
Viktor [21]

The depression in freezing point is related to molality of solution as follows:

\Delta T_{f}=k_{f}m

Here, k_{f} is freezing point depression constant, for cyclohexane it is equal to 20°C kg/mol.

The value of freezing-point depression is 2.5 °C, molality can be calculated as follows:

m=\frac{\Delta T_{f}}{k_{f}}=\frac{2.5 ^{o}C}{20 ^{o}C kg/mol}=0.125 mol/kg

Molality is defined as number of moles of solute in 1 kg of solvent.

Here, solvent is cyclohexane, its volume is given 20.0 mL and density is 0.779 g/mol thus, mass of cyclohexane can be calculated as follows:

m=d\times V=0.779 g/mL\times 20 mL=15.58 g

Converting this into kg,

1 g=10^{-3} kg

Thus, 15.58 g will be 0.01558 kg.

Now, number of moles of unknown solute is related to its mass and molar mass as follows:

n=\frac{m}{M}

Putting the values of mass of solute which is 0.2436 or 0.0002436 kg

n=\frac{ 0.0002436 kg}{M}

Now, expression for molality of solution is:

m=\frac{n_{solute}}{m_{solvent}}

Putting all the values,

0.125 mol/kg=\frac{0.0002436 kg}{M\times 0.01558 kg}

Or,

0.125 mol/kg=\frac{0.015635}{M}

On rearranging,

M=\frac{0.015635}{0.125 mol/kg}=0.1250 kg/mol

Or,

M=0.125 kg/mol(\frac{1000 g}{1 kg})=125 g/mol

Therefore, molar mass of unknown sample is 125 g/mol

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4 years ago
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Answer:

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When the sun, moon, and Earth are in alignment (at the time of the new or full moon), the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides — both commonly called spring tide

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