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Gala2k [10]
3 years ago
9

The range of human hearing extends from approximately 20 Hz to 20000 Hz. Find the wavelength for 20 Hz when the speed of sound i

n air is 359 m/s. Answer in units of m.
Physics
1 answer:
sweet [91]3 years ago
6 0

Answer:

Wavelength of sound wave corresponding to 20 Hz frequency will be 17.95 m

Explanation:

We have given that range of human hearing extends from 20 Hz and 20000 Hz

Velocity of sound wave is given 359 m /sec

We have to find the wavelength of the sound wave corresponding to 20 Hz

We know that velocity of sound wave is given by v=\lambda f, here v is velocity \lambda is wavelength and f is frequency

So 359=\lambda \times 20

\lambda =17.95m

So wavelength of the sound wave corresponding to 20 Hz frequency will be 17.95 m

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for max :

100 feet in 10 secs

for molly :

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Explanation:

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How to tell if a circuit is connected in.a series.or parallel?
stepladder [879]

Series circuits split the voltage of resistors, so if you see several diodes connected <em>in series </em>or all next to each other, just a complete loop, it will be in series.

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7 0
3 years ago
A small, 300 g cart is moving at 1.20 m/s on an air track when it collides with a larger, 2.00 kg cart at rest?
stiv31 [10]

Answer:

The speed of the large cart after collision is 0.301 m/s.

Explanation:

Given that,

Mass of the cart, m_1 = 300\ g = 0.3\ kg

Initial speed of the cart, u_1=1.2\ m/s

Mass of the larger cart, m_2 = 2\ kg

Initial speed of the larger cart, u_2=0

After the collision,

Final speed of the smaller cart, v_1=-0.81\ m/s (as its recolis)

To find,

The speed of the large cart after collision.

Solution,

Let v_2 is the speed of the large cart after collision. It can be calculated using conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

m_1u_1+m_2u_2-m_1v_1=m_2v_2

v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}

v_2=\dfrac{0.3\times 1.2+0-0.3\times (-0.81)}{2}

v_2=0.301\ m/s

So, the speed of the large cart after collision is 0.301 m/s.

4 0
3 years ago
The siren on an ambulance emits a sound of frequency 2.80×103Hz. If the ambulance is traveling at 26.0 m/s (93.6 km/h or 58.2 mi
Norma-Jean [14]

To solve this problem it is necessary to apply the concepts related to the described wavelength through frequency and speed. Mathematically it can be expressed as:

\lambda = \frac{v}{f}

Where,

\lambda = Wavelength

f = Frequency

v = Velocity

Our values are given as,

f = 2.8*10^3Hz

v = 340m/s \rightarrow Speed of sound

Keep in mind that we do not use the travel speed of the ambulance because we are in front of it. In case it approached or moved away we should use the concepts related to the Doppler effect:

Replacing we have,

\lambda = \frac{340}{2.8*10^3}

\lambda = 0.1214m

Therefore the frequency that you hear if you are standing in from of the ambulance is 0.1214m

5 0
3 years ago
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