Average speed =
(distance covered during some period of time)
divided by
(length of time to cover that distance).
<span>As it is uniform circular motion therefore speed is constant. Therefore we can rule out option B. Also in circular motion the direction of velocity vector changes therefore velocity can't be constant. Therefore option B is incorrect as well. Also centripetal acceleration is always towards the center so option D is wrong as well.
That implies
option A is correct.</span>
For a wave is described by y=0.0200 sin (kx - ωt) , where , ω = 3.62 rad/s, x and y are in meters, and t is in seconds, the wavelength = 2.978
<h3>How to solve for the wavelength</h3>
What is wave speed?
This is used to refer to the speed at which a wave is moving. It is the product of frequency and wave number
Given data
y=0.0200 sin (kx - ωt)
ω = 3.62 rad/s
y are in meters
t is in seconds
k = 2.11 rad/m
k = wavenumber = 2 * pi / wavelength
wavelength = 2 * pi / wavenumber
wavelength = 2 * pi / 2.11
wavelength = 2.978
Read more on wavelength here
brainly.com/question/10728818
#SPJ4
-- In order to achieve constant verlocity, the net force on the mass must be zero. So if there ARE any forces acting on it, they must be balanced.
-- There is already a force on the mass that can't be eliminated . . . the force of gravity.
-- That force due to gravity is (mass x gravity) = (25 kg)(9.8 m/s²) = <em><u>245N</u></em> in the <u><em>downward</em></u> direction.
-- In order to 'balance' the forces and make them add up to zero, we have to provide another force of <em>245N</em>, all in the <em>upward</em> direction.
-- Then the forces on the object will be balanced, the NET force on it will be zero, and whichever way you start it moving, it will continue to move at a cornstant verlocity.
Answer:
We know that the speed of sound is 343 m/s in air
we are also given the distance of the boat from the shore
From the provided data, we can easily find the time taken by the sound to reach the shore using the second equation of motion
s = ut + 1/2 at²
since the acceleration of sound is 0:
s = ut + 1/2 (0)t²
s = ut <em>(here, u is the speed of sound , s is the distance travelled and t is the time taken)</em>
Replacing the variables in the equation with the values we know
1200 = 343 * t
t = 1200 / 343
t = 3.5 seconds (approx)
Therefore, the sound of the gun will be heard at the shore, 3.5 seconds after being fired