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Paul [167]
3 years ago
12

An astronaut on the moon pushes with her left hand on a small rock and with her right hand on a large rock. Each hand pushes wit

h a force of 15 N. The small rock has mass 2 kg and the large rock has mass 8 kg. What forces do the rocks exert on the astronaut?
The small rock exerts a pushing force of 20 N; the large rock exerts a pushing force of 78 N.

The small rock exerts a pushing force of 3 N; the large rock exerts a pushing force of 12 N.

Each rock exerts a pushing force of 7.5 N.

Each rock exerts a pushing force of 15 N.
Physics
2 answers:
trapecia [35]3 years ago
7 0

Both would go 15N. Hoped I helped!

Marina CMI [18]3 years ago
4 0

Answer:

<h2>Each rock exerts a pushing force of 15 N.</h2>

Explanation:

The clue here is that the astronaut pushes with a force of 15N.

To understand this better we need to recur to Newton's third law which states

For every action (force), there's an equal and opposite reaction.

So, we know that the astronaut pushed both rocks with 15N force. By Netwon's third law, both rocks exert a force of 15N back, because such reaction must be equal.

Therefore, the right answer is the last choice: <em>Each rock exerts a pushing force of 15 N.</em>

<em />

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Acceleration is defined as the rate of change for which characteristic?
Alenkasestr [34]

1) C. velocity

Acceleration is defined as the rate of change of velocity per unit time. In formulas:

a=\frac{\Delta v}{\Delta t}

where

\Delta v is the change in velocity

\Delta t is the time interval

Therefore, the correct answer is C. velocity.


2) A. 9.8m/s/s

Earth's gravity is a force, so it produces an acceleration on every object with mass located on the Earth's surface. This acceleration can be calculated, as it is given by the formula

g=\frac{GM}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

r=6.37\cdot 10^6 m is the Earth's radius

By substituting these numbers into the formula, one can find that the acceleration due to Earth's gravity is g=9.81 m/s^2.

7 0
4 years ago
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Which layer of the earth includes the ozone layer
Rus_ich [418]
Troposphere is the answer
7 0
3 years ago
A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th
vladimir1956 [14]

Answer:

Force, F=2.27\times 10^4\ N

Explanation:

Given that,

Mass of the bullet, m = 4.79 g = 0.00479 kg

Initial speed of the bullet, u = 642.3 m/s

Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

F.d=\dfrac{1}{2}m(v^2-u^2)

Finally, it stops, v = 0

F.d=-\dfrac{1}{2}m(u^2)

F=\dfrac{-mu^2}{2d}

F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}

F = -22713.92 N

F=2.27\times 10^4\ N

So, the magnitude of the force that stops the bullet is 2.27\times 10^4\ N

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3 years ago
A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. What is the m
Akimi4 [234]

Answer:

8.6 m

Explanation:

The motion of a soccer ball is a motion of a projectile, with a uniform motion along the horizontal (x-) direction and an accelerated motion along the vertical (y-) direction, with constant acceleration a=g=-9.8 m/s^2 towards the ground (we take upward as positive direction, so acceleration is negative).

The initial velocity along the vertical direction is

v_{y0} = v_0 sin \theta = (26 m/s)(sin 30^{\circ})=13 m/s

Now we can consider the motion along the vertical direction only. the vertical velocity at time t is given by:

v_y(t)=v_{y0} +at

At the point of maximum height, v_y(t)=0, so we can find the time t at which the ball reaches the maximum height:

0=v_{y0}+at\\t=-\frac{v_{y0}}{a}=-\frac{13 m/s}{-9.8 m/s^2}=1.33 s

And now we can use the equation of motion along the y-axis to find the vertical position of the ball at t=1.33 s, which corresponds to the maximum height of the ball:

y(t)=v_{y0}t + \frac{1}{2}at^2=(13 m/s)(1.33 s)+\frac{1}{2}(-9.8 m/s^2)(1.33 s)^2=8.6 m

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3 years ago
Which of the following is a true statement about learning?
Furkat [3]

Answer:

B. learning happens through experience and practice.

3 0
3 years ago
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