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Paul [167]
3 years ago
12

An astronaut on the moon pushes with her left hand on a small rock and with her right hand on a large rock. Each hand pushes wit

h a force of 15 N. The small rock has mass 2 kg and the large rock has mass 8 kg. What forces do the rocks exert on the astronaut?
The small rock exerts a pushing force of 20 N; the large rock exerts a pushing force of 78 N.

The small rock exerts a pushing force of 3 N; the large rock exerts a pushing force of 12 N.

Each rock exerts a pushing force of 7.5 N.

Each rock exerts a pushing force of 15 N.
Physics
2 answers:
trapecia [35]3 years ago
7 0

Both would go 15N. Hoped I helped!

Marina CMI [18]3 years ago
4 0

Answer:

<h2>Each rock exerts a pushing force of 15 N.</h2>

Explanation:

The clue here is that the astronaut pushes with a force of 15N.

To understand this better we need to recur to Newton's third law which states

For every action (force), there's an equal and opposite reaction.

So, we know that the astronaut pushed both rocks with 15N force. By Netwon's third law, both rocks exert a force of 15N back, because such reaction must be equal.

Therefore, the right answer is the last choice: <em>Each rock exerts a pushing force of 15 N.</em>

<em />

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A rod (length = 80 cm) with a rectangular cross section (1.5 mm × 2.0 mm) has a resistance of 0.20 Ω. What is the resistivity of
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Answer:

The resistivity of the material used to make the rod is ρ= 7.5 * 10⁻⁷ Ω.m

Explanation:

R= 0.2 Ω

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3 years ago
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Answer:

m = 4.44 [g]

Explanation:

This is a problem related to heat transfer and thermodynamics. The second law of thermodynamics tells us that heat goes in only one direction, from the highest temperature substance to the lowest temperature. In this case the heat goes from tea to ice. The heat transfer process could be defined as the heat rejection of one body will be equal to the Heat received by another body.

Q_{out}=Q_{in}\\Q_{out}=m*cp*(T_{f}-T_{i})

Where:

m = mass = 177[g] = 0.177[kg]

Cp = specific heat = 4186 [J/kg*C]

T_f = 29.1 [°C]

Ti = 31.1 [°C]

Q = 0.177*4186*(29.1 - 31.1)

Q = - 1481.8 [J]

Note: The negative sign means that the heat is rejected.

Recall that the heat rejected is equal to the heat transferred

As the ice is going through a phase change, the fusion latent heat should be used, i.e. when it passes from solid to liquid. The heat transfer for this process is calculated with the following expression.

Qin = m *hf

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1481.8 = m * 333700

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Explanation:

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Answer: Oblique impact

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When the motion of one or both of the particles is at an angle to the line of impact, the impact is said to be oblique impact.

On the other hand, when the directions of motion of the two colliding particles are moving along a line of impact, then it's refered to as central impact.

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