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Paul [167]
3 years ago
12

An astronaut on the moon pushes with her left hand on a small rock and with her right hand on a large rock. Each hand pushes wit

h a force of 15 N. The small rock has mass 2 kg and the large rock has mass 8 kg. What forces do the rocks exert on the astronaut?
The small rock exerts a pushing force of 20 N; the large rock exerts a pushing force of 78 N.

The small rock exerts a pushing force of 3 N; the large rock exerts a pushing force of 12 N.

Each rock exerts a pushing force of 7.5 N.

Each rock exerts a pushing force of 15 N.
Physics
2 answers:
trapecia [35]3 years ago
7 0

Both would go 15N. Hoped I helped!

Marina CMI [18]3 years ago
4 0

Answer:

<h2>Each rock exerts a pushing force of 15 N.</h2>

Explanation:

The clue here is that the astronaut pushes with a force of 15N.

To understand this better we need to recur to Newton's third law which states

For every action (force), there's an equal and opposite reaction.

So, we know that the astronaut pushed both rocks with 15N force. By Netwon's third law, both rocks exert a force of 15N back, because such reaction must be equal.

Therefore, the right answer is the last choice: <em>Each rock exerts a pushing force of 15 N.</em>

<em />

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. Consider a fully extended arm that is rotating about the shoulder such that with a shoulder-to-hand length of 30 cm. If the ar
Rainbow [258]

Answer:

13.309 m/s²

Explanation:

Length from shoulder to hand, l = 30 cm = 0.3 m

initial velocity, u = 1 m/s

final velocity, v = 2.5 m/s

time, t = 3 s

Let the tangential acceleration is a.

by using first equation of motion

v = u + at

2.5 = 1 + 3 a

a = 0.5 m/s²

Let the centripetal acceleration is a'.

a' = v'²/l

a' = 2 x 2 / 0.3

a' = 13.3 m/s²

The tangential acceleration and the centripetal acceleration are both perpendicular to each other. So, the net acceleration is given by

A=\sqrt{a^{2}+a'^{2}}

A=\sqrt{0.5^{2}+13.3^{2}}

A = 13.309 m/s²

3 0
3 years ago
What is the resistance of the coil A at 600 kelvin if its resistance at 300 kelvin is 50 ohms? (Assume the temperature coefficie
leonid [27]

155Ω

Explanation:

R = R ref ( 1 + ∝ ( T - Tref)  

where R = conduction resistance at temperature T

R ref = conductor resistance at reference temperature

∝ = temperature coefficient of resistance for conductor

T = conduction temperature in degrees Celsius

T ref = reference temperature that ∝ is specified at for the conductor material

T = 600 k - 273 k = 327 °C

Tref = 300 - 273 K = 27 °C

R = 50 Ω ( 1 + 0.007 ( 327 - 27) )

R = 155Ω

8 0
3 years ago
Read 2 more answers
Calculate the frequency if the number of revolutions is 300 and the paired poles are 50.
Andrei [34K]

Answer: A

Explanation: We know that f=p*n

f=50*300=15000 Hz = 15kHz.

Have a great day! <3

3 0
1 year ago
Plz hurry brainliest guaranteed
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Answer is B raindrops conduct electricity from clouds to the ground.
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2 years ago
When an object like a tree is illuminated by the sun, and you are looking toward the tree, light rays leave the object _________
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Objects absorb and reflect light differently depending on their physical characteristics, such as their shape or composition. Thanks to the reflection we can see the objects. Reflection can be defined as the change of direction of a wave, which, when in contact with the separation surface between two changing means, returns to the point where it originated. When the light illuminates the object, such as the tree, the rays of light will disperse in all directions allowing observation.

The correct answer is A. From every point on the surface of the tree, and in every direction

6 0
3 years ago
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